<h2>
Speed with which it return to its initial level is 100 m/s</h2>
Explanation:
We have equation of motion v² = u² + 2as
Initial velocity, u = 100 m/s
Acceleration, a = -9.81 m/s²
Final velocity, v = ?
Displacement, s = 0 m
Substituting
v² = u² + 2as
v² = 100² + 2 x -9.81 x 0
v² = 100²
v = ±100 m/s
+100 m/s is initial velocity and -100 m/s is final velocity.
Speed with which it return to its initial level is 100 m/s
Answer:
Explanation:
given,
F = 14.1 i + 0 j + 5.1 k
displacement = 6 m
Assuming block is moving in x- direction
we know,
dW = F dx
![W = F[x]_0^6](https://tex.z-dn.net/?f=W%20%3D%20F%5Bx%5D_0%5E6)
hence, work done by the force is equal to
Transverse wave = at right angles to the direction of the motion of the wave
in transverse wave medium particles will move perpendicular to the direction of motion of medium particles
they all are perpendicular to wave always
Longitudinal wave = back and forth in the direction of the motion of the wave
in longitudinal waves medium particles will move in the direction of wave and the motion is always in back and forth type
electromagnetic wave = alternating waves moving at right angles to each other
electromagnetic waves are combination of electric field and magnetic field which oscillates perpendicular to wave as well as they are perpendicular to each other
B. Metals are usually defined to be from group 1 to group 13 in the periodic table which has 1-3 electrons in the outermost shell. They easily give them up which explains their conductivity.
Starting velocity (u)=0
acceleration (a) = 9.8
time (t) = 1.5
final velocity (v) =?
v=at+u
v=9.8(1.5)+0
v=14.7m/s2
