Question

The velocity of a 150 kg cart changes from 6.0 m/s to 14.0 m/s. What is the magnitude of the impulse that acted on it?

Answer 1

M = 150 kg.

Final velocity, v = 14 m/s

Initial Velocity, u = 6 m/s

Impulse =  m(v - u)
 
             = 150*(14 - 6)
           
             =  150*8 = 1200 kgm/s  or 1200 Ns 

Answer 2

Answer: The magnitude of impulse acted on the cart will be 1200 kg.m/s

Explanation:

Impulse is defined as the product of mass of the object and the change in its velocity. It is basically the change in momentum of the body.

Mathematically,

$J=m\Delta v$

where,

J = Impulse

m = mass of the object

$\Delta v=v_2-v_1$ = change in the velocity

We are given:

$m=150kg\\v_1=6m/s\\v_2=14m/s\\J=?kg.m/s$

Putting values in above equation, we get:

$J=150kg\times (14-6)m/s=1200kg.m/s$

Hence, the magnitude of impulse acted on the cart will be 1200 kg.m/s