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Genrish500 [490]
3 years ago
13

baseball player hits a line drive estimated to have traveled 145 meters the ball leaves the bat with a horizontal velocity of 40

.0 m/s . how much time was the ball in the air
Physics
1 answer:
Taya2010 [7]3 years ago
8 0

Answer:

3.63 s

Explanation:

Since distance d = vt where v = velocity and t = time taken to cover the distance.

Now, the baseball traveled a distance of d = 145 m with a horizontal velocity of 40.0 m/s.

So, making t subject of the formula,

t = d/v

Substituting the values of d and v we have

t = 145 m/40.0 m/s

= 3.625 s

≅ 3.63 s

So the time the ball was in the air is 3.63 s

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6) The temperature of 10 kg of a substance rises by 55°C when heated. Calculate the
Anna [14]

Answer:

121

Explanation:

8 0
3 years ago
A 2.0 kg wood block is launched up a wooden ramp that is inclined at a 30° angle. The block’s initial speed is 10 m/s. What vert
Romashka [77]

Answer:

Vertical Height = 0.784 meter, Speed back at starting point = 10 m/s

Explanation:

Given Data:

V is the overall velocity vector, Vi and Ui are its initial vertical and horizontal components

R = 10 m/s\\ Projection Angle (theta) = 30 degrees\\Vi   = 10*sin(30) = 5 m/s\\Ui  = 10*cos(30) = 8.66 m/s

To find:

Max Height h achieved

Calculation:

1) Using the 3^{rd} equation of motion, we know

2*a*s = Vf^{2}  - Vi^{2}

2) In terms of gravity g height h and  the vertical component of Velocity Vf , Vi.

3) As Vf = 0 as at maximum height the vertical component of velocity is zero maximum height achieved

2*g*h = Vf^{2}  -Vi^{2}

putting values

4) h = 0.784 m/s

5) As for the speed when it reaches back its starting point, it will have a speed similar to its launching speed, the reason being the absence of air friction (Air drag)

3 0
4 years ago
It takes me 12s to lift a box upward with 20 N of force to a height of 45m. What was my power output ?
Finger [1]

Answer:

75Watts

Explanation:

Given parameters:

Time  = 12s

Force applied  = 20N

Height  = 45m

Unknown:

Power output  = ?

Solution:

Power is defined as the rate at which work is done.

 It is mathematically expressed as;

        Power  = \frac{work done}{time}

Work done  = force x distance  = 20 x 45  = 900J

        Power  = \frac{900}{12}   = 75Watts

6 0
3 years ago
A golf ball has a mass of 120g. Calculate its increase in mass when it is travelling at 40ms1. What is this as a percentage of i
kicyunya [14]

Answer:

Percentage=8.889\times 10^{-13}%

Explanation:

From special theory of relativity the dynamic mass m is related with the rest mass m_{0}of the body as

m=\frac{m_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }

Here, c is the speed of light and v is the velocity of object.

Given mass of the golf ball is 120 g.

m=\frac{120 }{\sqrt{1-\frac{(40)^{2} }{(3\times 10^{8} )^{2} } } }\\m=120(1-\frac{(40)^{2} }{(3\times 10^{8}) ^{2} })^{-\frac{1}{2} } \\

Now applying the binomial theorem and solve the above equation.

m=(1+\frac{1}{2}(\frac{40}{3\times 10^{8} }) ^{2} )\\m=120(1+8.889\times 10^{-15})

Therefore, increase in mass is,

\Delta m=120\times 8.889\times 10^{-15} \\\Delta m=10.6668\times 10^{-13} g

Now percentage of increase in mass with rest mass is,

Percentage=\frac{10.6668\times 10^{-13} g}{120g} \times 100\\Percentage=8.889\times 10^{-13}

Therefore, the percentage of increase in mass with rest mass is Percentage=8.889\times 10^{-13}.

4 0
4 years ago
If you wanted to increase the gravitational force between two objects what would you do
adelina 88 [10]
Double the force on the object
6 0
4 years ago
Read 2 more answers
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