Answer:
this is because the van der waals forces or also known as induced dipole-dipole interactions increase because more electrons are present within an atom as you go down
Explanation:
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<h3>
Answer:</h3>
Gas law : Boyle's law
New pressure: 66.24 atm
<h3>
Explanation:</h3>
Concept tested: Gas laws (Boyle's law)
<u>We are given,</u>
- Initial pressure, P₁ = 2.86 atm
- Initial volume, V₁ = 8472 mL
- New volume, V₂ IS 365.8 mL
We need to determine the new pressure, P₂
- According to Boyle's law , the volume of a fixed mass of a gas and the pressure are inversely proportional at constant temperature.
- That is,
- This means , PV = k (constant)
- Therefore; P₁V₁ = P₂V₂
- Rearranging the formula, we can get the new pressure, P₂
P₂ = P₁V₁ ÷ V₂
= (2.86 atm × 8472 mL) ÷ 365.8 mL
= 66.24 atm
Therefore, the new pressure is 66.24 atm
Answer:
2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl
Explanation:
When we balance a chemical equation, what we are trying to do is to achieve the same number of atoms for each element on both sides of the arrow. On the right of the arrow is where we can find the products, while the reactants are found on the left of the arrow.
We usually balance O and H atoms last.
AsCl₃ + H₂S → As₂S₃ +HCl
<u>reactants</u>
As --- 1
Cl --- 3
H --- 2
S --- 1
<u>products</u>
As --- 2
Cl --- 1
H --- 1
S --- 3
2 AsCl₃ + H₂S → As₂S₃ +HCl
<u>reactants</u>
As --- 2
Cl --- 6
H --- 2
S --- 1
<u>products</u>
As --- 2
Cl --- 1
H --- 1
S --- 3
The number of As atoms is now balanced.
2 AsCl₃ + 3 H₂S → As₂S₃ +HCl
<u>reactants</u>
As --- 2
Cl --- 6
H --- 6
S --- 3
<u>products</u>
As --- 2
Cl --- 1
H --- 1
S --- 3
The number of S atoms is now equal on both sides.
2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl
<u>reactants</u>
As --- 2
Cl --- 6
H --- 6
S --- 3
<u>products</u>
As --- 2
Cl --- 6
H --- 6
S --- 3
The equation is now balanced.
Cold blooded animal? it’s a bit vague sorry
