Answer:
<em>lithosphere</em><em> </em><em>(land)</em>
<em>hydrosphere (water)</em>
<em>biosphere</em><em> </em><em>(living things)</em>
<em>atmosphere (air).</em>
C) 24
Explanation:
When a radioactive isotope of Vanadium, V decays by producing a beta particle and gamma rays, the atomic number will be 24.
Vanadium is the 23rd element on the periodic table.
It has a mass number of 51.
atomic number is 23
⁵¹₂₃V
A beta particle is symbolized as °₋₁B
Gamma rays are represented by Y
Now to the equation:
⁵¹₂₃V → ₐⁿK + °₋₁B + Y
In a nuclear reaction the mass an atomic number is conserved
51 = n + 0
n = 51
23 = a -1
a = 24
We can see that the nuclide formed will have an atomic number of 24
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It would be +3
Since the number of protons and electrons must be equal in an atom for it to be neutral, if it looses electrons it becomes positively charged ion and if it gains electrons it becomes negatively charged ion.
The density : 21.63 g/L
<h3>Further explanation</h3>
The gas equation can be written
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
T = 65+273=338 K
P=2.36 atm
MW Iodine gas (I₂)=254
The density :
Answer:
0.0991 M
Explanation:
Step 1: Write the neutralization reaction between oxalic acid and sodium hydroxide.
H₂C₂O₄ + 2 NaOH = Na₂C₂O₄ + 2 H₂O
Step 2: Calculate the moles of oxalic acid
The molar mass of H₂C₂O₄ is 90.03 g/mol. The moles corresponding to 153 mg (0.153 g) are:
Step 3: Calculate the moles of sodium hydroxide
The molar ratio of H₂C₂O₄ to NaOH is 1:2.
Step 4: Calculate the molarity of sodium hydroxide
