It will behave has a conductor in high voltage
Answer:
covalent bond
Explanation:
The bond which is most common in the organic molecules is the covalent bond which involves sharing of the electrons between the two atoms.
Glycosidic bond, also known as glycosidic linkage is type of the covalent bond which joins carbohydrate molecule to other group that may not or may be a carbohydrate.
Glycosidic bond is the bond which is formed between hemiacetal or hemiketal group of the saccharide and hydroxyl group of compounds like alcohol.
Answer: option D, Attractive forces form between polar water molecules and polar glass molecules in the cylinder.
Explanation:
1) The curved surface of water in the cylinder shown in the figure is named concave meniscus.
2) The situation shown reflects two forces that oppose each other.
These are the adhesive force and the cohesiive force.
3) The adhesive force is the of attraction between molecules of different substances, while the cohesive force is the attraction between molecules of the same substance.
4) Water has a strong cohesive force property in virtue of the hydrogen bonds (the particles of water tends to remain together due to the high intensity of the hydrogen bonds). This is why water form drops.
But also, there is a strong cohesive force between the polar water molecules and the polar glass molecules in the cylinder.
The concave meniscus is the result of the fact that the adhesive force between the surface of the glass cylinder and the molecules of water overcomes the cohesive force of the water molecules.
Given the temperature 746 K and activity of Pb equal to 0.055. The mole fraction of Pb is 0.1. So, the mole fraction of Sn = 0.9.Activity coefficient, γ = 0.055 / 0.1 = 0.55.The expression for w=ln〖γ_Pb x RT〗/(X_Sn^2 )=(-0.5978 x 8.314 J/(mol K ) x 746 K)/(0.9 x 0.9)= -4577.7 J= -4578 J
Now we use the computed value above and new temperature 773 K. The mole fraction of Sn and Pb are 0.5 and 0.5 respectively. Calculate the activity coefficient in the following manner.lnγ_Sn=w/RT X_Pb^2=(-4578 J)/(8.314 J/mol x 773 K) x 0.5 x 0.5= -0.718lnγ_Sn=exp(-0.178)=0.386The activity of Sn= γ_Sn x X_Sn=0.386 x 0.5=0.418
w of the system is -4578 J and the activity of Sn in the liquid solution of xsn at 500 degree Celsius is 0.418
