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3 years ago

I need help with question number one please help?

Mathematics

1 answer:

Kisachek [45]3 years ago

5 0

1) Area of trapezoid =1/2(base 1 +base 2)* height

$A= \frac{23 \frac{1}{3}+4 \frac{2}{3} }{2} *(12 \frac{3}{4} ) = \frac{27 \frac{3}{3} }{2} *( \frac{51}{4} ) = \frac{28}{2} * \frac{51}{4} = \frac{7*51}{2} = \frac{357}{2} =178 \frac{1}{2} x^{2}$

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Dominik [7]

Answer:

12 units

Step-by-step explanation:

Properties of Rhombus:

1. length of all sides are equal.

2. Diagonals bisect each other at right angles

As the length of all sides are equal,

JM = JK

3x = 2x + 4

Subtract 2x from both sides,

3x - 2x = 4

x = 4

JM = 3*4 = 12 units

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2 years ago

The function h=-16t^2 +1700 gives you the height h, of an object in feet, at t seconds. How long will it take the object to hit

garik1379 [7]

Answer:

The object will hit the ground after 10.308 seconds.

Step-by-step explanation:

h(t) = -16t² + 1700

If you graphed this function, the object would be shown hitting the ground when it crosses the x-axis, in other words, when h = 0. So, to find the answer, just set h(t) equal to 0 and solve.

-16t² + 1700 = 0 Plug this into a calculator if you have one.

t = -10.308 and t = 10.308

Since time can't be negative, your answer will be the positive value, 10.308.

6 0

3 years ago

Consider circle O. If AE = 7, EC = 2, and BE = 4, what is ED?

miv72 [106K]

The correct answer is 3.5

Two chords AC and BD are intersecting inside the circle. The Intersecting Chord Theorem states that when two chords intersect inside a circle, the products of their segments are equal.

Thus, for the given circle:
(AE) × (EC) = (BE) × (ED)

The lengths of the segments are
AE = 7
EC = 2
BE = 4
ED = ?

To solve for ED, we simply substitute the known values into the equation
$ED = \frac{7(2)}{4} = \frac{14}{4} = 3.5$

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Aleks04 [339]

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So you would end up with

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3 years ago

Look at photo because I don’t get it

steposvetlana [31]

Answer:

a) (-2,2), (-1,-1), (1,-1), (3,7)

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3 years ago

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