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hjlf
3 years ago
5

1

Mathematics
2 answers:
Alexeev081 [22]3 years ago
6 0

Answer:

The answer is y=-1/4x+11/16

Step-by-step explanation:

y-y=m(x-x1)

y-1=-1/4(x-(-5/4))

y-1=-1/4x-5/16

+1 +1

y=-1/4x+11/16

Fantom [35]3 years ago
6 0
It’s the second one
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(-6x + 3) + (X - 7) add linear expressions
Leni [432]
-6x + 3 + x - 7...when ur adding expressions such as this, and there is a plus sign in between them, the parenthesis are not needed.

we now combine like terms...
-6x + x = -5x
3 - 7 = -4

and we are left with : -5x - 4 <==
3 0
3 years ago
Please write the answer​
Travka [436]

\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)}  \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\  \\ \longrightarrow \sf \: 27 - 15 \\  \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}

6 0
3 years ago
K+ OH-<br> What’s is the formula for this
ruslelena [56]

Answer:

check the periodic table

3 0
3 years ago
For f(x) = 3x^2 – X+5, 2f (-3) - f(4)=
Alenkinab [10]

Answer:

3x^2-x+5.2f\left(-3\right)-f\left(4\right) =

3x^2-x-19.6f

Step-by-step explanation:

3x^2-x+5.2f\left(-3\right)-f\left(4\right)

=3x^2-x-5.2f\cdot \:3-f\cdot \:4

=3x^2-x-15.6f-4f

=3x^2-x-19.6f

8 0
3 years ago
Can someone help me
FromTheMoon [43]
BC is 8.7 
CA is 20
hope this helps
6 0
3 years ago
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