The total distance between the two women would simply be
the sum of the hypotenuse formed by the triangular path they created.
For each women:
<span>c^2 = a^2 + b^2</span>
c^2 = 3^2 + 4^2
c^2 = 9 + 16
c^2 = 25
c = 5 m
Therefore the distance between the two is:
distance between the two women = 2 * c
<span>distance between the two women = 10 m</span>
The solution is where both lines intersect. First find the x-coordinate which we will find by going to the left two units. That means x = -2. Now going up one unit, which gives us y = 1
(-2, 1)
Answer: 15, -8
Step-by-step explanation:
Omg I’m so sorry I’m not giving you your answer but I need to comments so I can post my questions hope you get your answer!
Dy/dx = (dy/dt) / (dx/dt)
dy/dt = 2bt
dx/dt = 3at^2
therefore dy/dx = 2bt/3at^2
dy/dx = 2b/3at
