Yuh, ooh, brr, brr
Gucci gang, ooh
<span>(That's it right there, Gnealz)</span>
Yuh, Lil Pump, yuh
Gucci gang, ooh
<span>(Ooh, Bi-Big Head on the beat)</span>
<span>Yuh, brr</span>
Answer:
17.7 cm^2
Step-by-step explanation:
Use trig to find the height of the triangle. Then the area is bh/2.
Extend side BC to the right until it is vertically below point A. Draw a segment from point A vertically down until it intersects the extension of side BC. Call the point of intersection D. <D is a right angle.
Use triangle ABD to find the height, AD, of triangle ABC.
For <B of 37 deg, AD is the opposite leg. AB is the hypotenuse. The trig ratio that relates the opposite lefg to the hypotenuse is the sine.
sin B = opp/hyp
sin 37 deg = AD/13.1
AD = 13.1 * sin 37 deg
AD = 7.9
AD is the height of triangle ABC. BC is the base. We can find the area of triangle ABC.
area = bh/2
area = (4.5 cm)(7.9 cm)/2
area = 17.7 cm^2
Step-by-step explanation:
72/64=x/8
=> x = (72×8)/64
=> x = 9.
hope this helps you.
<h3>
Answer: E) x^5</h3>
=====================================================
Explanation:
We simply take half of the exponent 10 to get 5. This applies to square roots only.
So the rule is 
A more general rule is
![\sqrt[n]{a^b} = a^{b/n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Eb%7D%20%3D%20a%5E%7Bb%2Fn%7D)
If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.
