Expand the expression 2(30x-24)

What is the answer to > solve 4cos (theta/3) -2 = 0, over [0, 4pi)

Vesna [10]

Hello from MrBillDoesMath!

Answer:

@ = pi/3 (or 60 degrees) or @ = 7 pi/3 (or 420 degrees)

Discussion:

Let "@' denote the angle "theta". We are asked to find @ in the interval [0, 4 pi)

where

4cos(@) - 2 = 0. Adding 2 to both sides

4 cos(@) - 2 +2 = 2 =>

4 cos(@) = 2 Divide both sides by 4

cos(@) = 2/4 = 0.5

This implies that @ = pi/3 (or 60 degrees) or @ = (pi/3 + 2pi) = 7 pi/3 (or 420 degrees)

Thank you,

MrB

5 0

3 years ago

Instructions:Select the correct answer from each drop-down menu. ∆ABC has vertices at A(11, 6), B(5, 6), and C(5, 17). ∆XYZ has

Akimi4 [234]

to compare the triangles, first we will determine the distances of each side

Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
Solving

∆ABC A(11, 6), B(5, 6), and C(5, 17)

AB = 6 units BC = 11 units AC = 12.53 units
∆XYZ X(-10, 5), Y(-12, -2), and Z(-4, 15)
XY = 7.14 units YZ = 18.79 units XZ = 11.66 units

∆MNO M(-9, -4), N(-3, -4), and O(-3, -15).

MN = 6 units NO = 11 units MO = 12.53 units
∆JKL J(17, -2), K(12, -2), and L(12, 7).
JK = 5 units KL = 9 units JL = 10.30 units
∆PQR P(12, 3), Q(12, -2), and R(3, -2)
PQ = 5 units QR = 9 units PR = 10.30 units
Therefore
we have the ∆ABC and the ∆MNO 
with all three sides equal ---------> are congruent
we have the ∆JKL and the ∆PQR
with all three sides equal ---------> are congruent

let's check

Two plane figures are congruent if and only if one can be obtained from the other by a sequence of rigid motions (that is, by a sequence of reflections, translations, and/or rotations).

1) If ∆MNO ---- by a sequence of reflections and translation --- It can be obtained ------->∆ABC

then ∆MNO ≅ ∆ABC

a) Reflexion (x axis)

The coordinate notation for the Reflexion is (x,y)---- >(x,-y)

∆MNO M(-9, -4), N(-3, -4), and O(-3, -15).

M(-9, -4)-----------------> M1(-9,4)

N(-3, -4)------------------ > N1(-3,4)

O(-3,-15)----------------- > O1(-3,15)

b) Reflexion (y axis)

The coordinate notation for the Reflexion is (x,y)---- >(-x,y)

∆M1N1O1 M1(-9, 4), N1(-3, 4), and O1(-3, 15).

M1(-9, -4)-----------------> M2(9,4)

N1(-3, -4)------------------ > N2(3,4)

O1(-3,-15)----------------- > O2(3,15)

c) Translation

The coordinate notation for the Translation is (x,y)---- >(x+2,y+2)

∆M2N2O2 M2(9,4), N2(3,4), and O2(3, 15).

M2(9, 4)-----------------> M3(11,6)=A

N2(3,4)------------------ > N3(5,6)=B

O2(3,15)----------------- > O3(5,17)=C

∆ABC A(11, 6), B(5, 6), and C(5, 17)

∆MNO reflection------- > ∆M1N1O1 reflection---- > ∆M2N2O2 translation -- --> ∆M3N3O3

The ∆M3N3O3=∆ABC

Therefore ∆MNO ≅ ∆ABC - > check list

2) If ∆JKL -- by a sequence of rotation and translation--- It can be obtained ----->∆PQR

then ∆JKL ≅ ∆PQR

d) Rotation 90 degree anticlockwise

The coordinate notation for the Rotation is (x,y)---- >(-y, x)

∆JKL J(17, -2), K(12, -2), and L(12, 7).

J(17, -2)-----------------> J1(2,17)

K(12, -2)------------------ > K1(2,12)

L(12,7)----------------- > L1(-7,12)

e) translation

The coordinate notation for the translation is (x,y)---- >(x+10,y-14)

∆J1K1L1 J1(2, 17), K1(2, 12), and L1(-7, 12).

J1(2, 17)-----------------> J2(12,3)=P

K1(2, 12)------------------ > K2(12,-2)=Q

L1(-7, 12)----------------- > L2(3,-2)=R

∆PQR P(12, 3), Q(12, -2), and R(3, -2)

∆JKL rotation------- > ∆J1K1L1 translation -- --> ∆J2K2L2=∆PQR

Therefore ∆JKL ≅ ∆PQR - > check list

6 0

3 years ago

A peregrine falcon can fly 322 kilometers per hour. How many meters per hour can the falcon fly

erma4kov [3.2K]

322,000 meters. Because there is 1,000 meters in a kilometer.

3 0

3 years ago

1. Given the below sequence: -1, -3, -5, -7, . . . (a) What are the next 3 terms? (b) Is this an arithmetic or geometric sequenc

valentinak56 [21]

Answer:

(a) -7 , - 9 , - 11

(b) Arithmetic sequence

(c) There is a common difference of -2

(d) -53

Step-by-step explanation:

(a) To find the next three terms , we must firs check if it is arithmetic sequence or a geometric sequence . For it to be an arithmetic sequence , there must be a common difference :

check :

-3 - (-1) = -5 - (-3) = -7 - (-5) = -2

This means that there is a common difference of -2 , which means it is an arithmetic sequence.

The next 3 terms we are to find are: 5th term , 6th term and 7th term.

$t_{5}$ = a + 4d

$t_{5}$ = - 1 + 4 ( -2 )

$t_{5}$ = -1 - 8

$t_{5}$ = - 9

6th term = a +5d

$t_{6}$ = -1 + 5(-2)

$t_{6}$ = -1 - 10

$t_{6}$ = - 11

$t_{7}$ = a + 6d

$t_{7}$ = -1 + 6 (-2)

$t_{7}$ = -1 - 12

$t_{7}$ = -13

Therefore : the next 3 terms are : -9 , -11 , - 13

(b) it is an arithmetic sequence because there is a common difference which is -2

(c) Because of the existence of common difference

(d) $t_{27}$ = a + 26d

$t_{27}$ = -1 + 26 ( -2 )

$t_{27}$ = -1 - 52

$t_{27}$ = - 53

5 0

3 years ago

How many is 56 weeks in months help

Vanyuwa [196]

Answer:

14 or also 1 year 2 months

3 0

3 years ago

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