Answer:
Option C.
Step-by-step explanation:
Total population = 1000 snails
AA = 160 snails
Aa = 480 snails
aa = 360 snails
Frequency of each type.



Now, we get

he frequency of the A allele in this population is 0.4.
Therefore, the correct option is C.
the answer to your question is 6/7 × 1 1/4 = 3/14
Step-by-step explanation:
2/5 ÷ 8/15
2/5 × 15/8
=3/4
Hope it helps ya