Answer:
The answer is 14.
Step-by-step explanation:
6(2+5)/3 would be the equation
12+30/3
42/3
14
U gots do 19000 * 6%
0.06 eqs 6% bb
19000 * 0.06 es $<u>1140 a YEAR</u>
a. Use the inclusion/exclusion principle.

b. By definition of conditional probability,

There are two ways to work this out: normal variables or using "imaginary" numbers.
Normal variables:
![(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}](https://tex.z-dn.net/?f=%20%287%2B2i%29%283-i%29%5C%5C%287%2A3%29%2B%5B7%2A%28-i%29%5D%2B%283%2A2i%29%2B%5B2i%2A%28-i%29%5D%5C%5C21-7i%2B6i-2i%5E%7B2%7D%5C%5C%5C%5C21-i-2i%5E%7B2%7D)
Imaginary numbers:
Using the result from earlier:

Now since

, then the expression becomes: