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sertanlavr [38]
3 years ago
5

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Mathematics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

8

Step-by-step explanation:

mom

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The zero of the polynomial 6x power 2 + 19 X - 77 is​
Iteru [2.4K]

Answer:

The zeros of the polynomial are x = 7 or x = -11/2

Step-by-step explanation:

The zeros of a polynomial refers to the solution of the polynomial.

6x^2 + 19x -77

6x^2-14x+ 33x -77

2x(x-7) + 11(x-7)

= (2x + 11)(x-7)

2x + 11 = 0

x-7 = 0

2x = -11

x = -11/2 = -5.5

and x-7 = 0

x = 7

So the zeros of the polynomial are x = 7 or x = -11/2

4 0
3 years ago
Points $M$, $N$, and $O$ are the midpoints of sides $\overline{KL}$, $\overline{LJ}$, and $\overline{JK}$, respectively, of tria
Ivan

The midpoint theorem states that the line joining the mid points of two sides of a triangle is parallel to the third and facing side and equal to half of the length of the third side

Based on the midpoint theorem, the area of triangle ΔLPQ is 63 square units

The reason the value of the area of triangle ΔLPQ as given above is correct is as follows:

The given parameters;

The midpoint of \overline {KL} = M; The midpoint of \overline {LJ} = N; The midpoint of \overline {JK} = O

The midpoint of \overline {NO} = P; The midpoint of \overline {OM} = Q; The midpoint of \overline {MN} = R

The area of triangle ΔPQR = 21

The required parameter:

Calculate the area of triangle ΔLPQ

Method:

The definition of midpoint, area ratio, and area of a triangle formula can be used to find the area of triangle ΔLPQ

Solution:

According to the midpoint theorem, we have;

\overline {QR} = (1/2) × \overline {NO}

\overline {PR} = (1/2) × \overline {OM}

\overline {PQ} = (1/2) × \overline {MN}

Given that \overline {QR} is parallel to \overline {ON}, and \overline {PR} is parallel to, we have;

∠MON = ∠PRQ

Similarly, we have, ∠MNO = ∠PQR

Therefore, ΔPQR is similar to triangle ΔMON, which is also similar to ΔJKS

The area of triangle ΔPQR = 21, by area ratio = (Side ratio)², we have;

The sides of ΔMON = 2 × The side length of ΔPQR

The area of triangle ΔMON = 2² × The area of ΔPQR

∴ The area of triangle ΔMON = 4 × 21

Similarly the area of ΔJKS = 4 × 4 × 21

PQ = JK/4

The area of LPQ = (1/2) × PQ × h

h = (3/4×JL) × sin(x°)

∴ The area of LPQ = (1/2)×JK/4×(3/4×JL) × sin(x°)

However; (1/2)×JK×JL× sin(x°) = Area of ΔJKS = 4 × 4 × 21

Therefore;

The area of ΔLPQ = (Area of ΔJKS)/4×(3/4) = (4 × 4 × 21)/4×(3/4) = 63

The area of triangle ΔLPQ = 63 square units

Learn more about the midpoint theorem here:

brainly.com/question/15227899

8 0
3 years ago
Anybody know this ? please help
Deffense [45]

Answer:

A.) <em>m ∠ ABD = m ∠ CBD</em>

Step-by-step explanation:

The line segment BD was constructed as an angle bisector, which means that ∠  ABC was split directly in half. This means that the two resulting angles are congruent.

5 0
3 years ago
Write an equation in slope intercept form for the line with slope negative three fourths and y intercept of negative one
Stells [14]

The slope intercept form is y=-\frac{-3x}{4}-1.

Solution:

Given data: slope = -\frac{3}{4} and y-intercept = –1

y-intercept means (x, y) = (0, –1)

Equation of a line for slope intercept form: y-y_1=m(x-x_1)

Here, x_1=0, y_1=-1 and m=-\frac{3}{4}.

⇒ y-(-1)=\frac{-3}{4} (x-0)

⇒ y+1=\frac{-3}{4} (x)

Do cross multiplication.

⇒ 4(y+1)=-3x

⇒ 4y+4=-3x

⇒ 4y=-3x-4

Divide both sides of the equation by 4.

⇒ y=-\frac{-3x}{4}-\frac{4}{4}

⇒ y=-\frac{-3x}{4}-1

Hence the slope intercept form is y=-\frac{-3x}{4}-1.

3 0
3 years ago
What is 1 7/8 + 2/8 ???
ludmilkaskok [199]

Answer:

The answer is 2.375.

Step-by-step explanation:

17 / 8 = 2.125.

2 / 8 = 0.25.

2.125 + 0.25 = 2.375.

4 0
3 years ago
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