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adell [148]
3 years ago
11

If Darren completed 25% of his science project on Monday, what percentage of his project is left to complete? A) 25% B) 50% C) 7

5% D) 125%
Mathematics
2 answers:
Vesna [10]3 years ago
5 0
75%   bc 25 + 75= 100

 Hope it helped
Pie3 years ago
4 0
75% I hope this helps you out 

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There are 30 kilograms of 10 percent apple juice how much more aplle juice does it need to get to 25 percent?
egoroff_w [7]

Answer:

45 kg of apple juice

Step-by-step explanation:

Divide 25% by 10%

The answer you get multiply it by 30

Take the answer you get subtract the 30 kg

7 0
2 years ago
What best describes the asymptote of an exponential function of the form f(x)=b^x?
horrorfan [7]

It depends on the value of b


Exponential functions are defined for positive values of the base [ŧex] b [/tex]. Also, they're not defined if b=1, or at least let's say that this is a trivial case, since it is the constant function 1.


Case 0<b<1:

If the base sits between 0 and 1, the exponential function is constantly decreasing. The explanation is quite intuitive, assume for the sake of simpleness that b is rational. If it sits between 0 and 1, it means that it can be written as a fraction p/q, with p<q. So, if you give a large exponent to b, you obtain


\frac{p^x}{q^x},\quad p^x \ll q^x \text{ as } x \to \infty


On the other hand, if you consider negative exponents, you switch numerator and denominator and then raise to the same exponent the fraction q/p, which gets larger and larger.


So, if 0<b<1, we have


\lim_{x \to -\infty} b^x = \infty,\qquad \lim_{x \to \infty} b^x = 0


and thus 0 is a horizontal asymptote as x tends to (positive) infinity.


Case b>1:

This case is very similar, except all roles are inverted. Now you start with a fraction p/q where p>q. So, with positive, large exponents you get


\frac{p^x}{q^x},\quad p^x \gg q^x \text{ as } x \to \infty


And as before, negative exponents switch numerator and denominator, so the fraction becomes q/p and thus you have


\lim_{x \to -\infty} b^x = 0,\qquad \lim_{x \to \infty} b^x = \infty


So, again, 0 is a horizontal asymptote, but this time for x tending towards negative infinite.

6 0
3 years ago
Read 2 more answers
Find the perimeter of the following shape:
Andreas93 [3]

Answer:

31

Step-by-step explanation:

6 0
3 years ago
Find the interquartile range of the data. 68, 15, 55, 5, 66, 42, 51, 12, 23 *
Elan Coil [88]

Answer:

72.5

Step-by-step explanation:

5, 12, 15, 23, 42, 51, 55, 66, 68

42 = median

Q1 median = 21

Q2 median = 93.5

93.5 - 21 = 72.5

         Hope this helped!!!

4 0
3 years ago
Given the function f(x) = 3x, find the value of f−1(81).
Shalnov [3]
Given the function f (x) = 3x, find the value of f-1 (81).
 For this case, the first thing you should do is rewrite the function.
 We have then:
 y = 3 ^ x
 From here, we clear the value of x:
 log3 (y) = log3 (3 ^ x)
 log3 (y) = x
 Then, we rewrite the function again:
 f (x) ^ - 1 = log3 (x)
 Now, we evaluate the inverse function for x = 81:
 f (81) ^ - 1 = log3 (81)
 f (x) ^ - 1 = 4
 Answer:
 the value of f-1 (81) is: 
 f (x) ^ - 1 = 4
4 0
3 years ago
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