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3 years ago

Help I can’t figure it out

Mathematics

1 answer:

sammy [17]3 years ago

5 0

25 salads were sold, as 5 salads w the were sold in the Caesar salad group, and 20% of the total salads were sold were Caesar. Therefore, 20% of 25 is 5, making the total number of salads sold equal to 25.

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antiseptic1488 [7]

Answer:

I think Its 47? if Im wrong Im very sorry.

Step-by-step explanation:

I added all of the numbers, and the sides without numbers, its simple just add all of the numbers together, I think

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3 years ago

Leona is having a birthday party on Sunday. Jeanette wants to know how many people will be coming. Leona tells her that there wi

konstantin123 [22]

Answer:77 and 87

Step-by-step explanation:

7×6=42 + 5+7=35/\ 35+42=77(first outcome)

7×6=42 + 5×9=45/\42+45=87 (second outcome.

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3 years ago

Linda already owns 7 necklaces, and additional necklaces are priced at 3 for a dollar. Write an equation that shows the relation

maksim [4K]

Answer:

95+5x=13x

I'd if this is right im not smart

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3 years ago

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A charter airline finds that on its Saturday flights from Philadelphia to London, all 120 seats will be sold if the ticket price

Nataliya [291]

Answer:

a) $P=3(120-s)+200$

b) $215 \leq P \leq 290$

Step-by-step explanation:

For this case we can use a linear model to solve the problem.

s) Create an equation to express the increase on the price tickets and the number of seats sold

$s$ number of seats, if w analyze the info given the number of seats after increase the price is given by $120-s$ .

And let P the price for the ticket. So after the increase in ticket price the expression for the increase is P-200.

We have an additional info, for each increase of $3 the number of setas decrease 1. And the equation that gives to us the price change in terms of the increase of price is:

$P-200=3(120-s)$

So then our linear equation is given by:

$P=3(120-s)+200$

b) Over a certain period, the number of seats sold for this flight ranged between 90 and 115. What was the corresponding range of ticket prices?

So for this case we just need to replace the limits into the linear equation and see what we got:

$P_L=3(120-90)+200=290$

$P_U=3(120-115)+200=215$

So the corresponding range of ticket prices is:

$215 \leq P \leq 290$

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3 years ago

On a map, Melbourne, Australia, is 22 centimeters from Sydney, Australia. The actual distance is 880 kilometers. If Canberra, Au

marysya [2.9K]

7 centimeters because you have to find how many kilometers are in each kilometer and that is 40 so then you divide 286 by 49 which is 7.15 then you round

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3 years ago

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