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2 years ago

BRAINIEST TO WHOEVER RIGHT

Mathematics

1 answer:

ioda2 years ago

3 0

Answer:

The range of data is 1 ,that is from -9 to 6

75% of data lies between -9 and 3.5 or 4

The onterquartile value is -1.5

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When Asher looks at the data he says that both Mrs. Jamison's class and Mr. Zimmerman's class has data that is skewed right. Do

Yuliya22 [10]

Answer:

Step-by-step explanation:

this isn’t an answer but did u did the answer to this because i need it. thanks

5 0

3 years ago

If a plane can travel 480 miles per hour with the wind and 400 miles per hour against the wind find the speed of the wind and th

pychu [463]

he is going 80 mph because he can go 480 mph and the wind is against him 400 mph and 480-400=80

Hope this helps!

Please give brainliest

7 0

3 years ago

(5/10)^4 in exponential form

Whitepunk [10]

Answer:

$6.25 \times {10}^{ - 2}$

Step-by-step explanation:

${ \bigg( \frac{5}{10} \bigg) }^{4} \\ \\ = {(0.5)}^{4} \\ \\ = 0.0625 \\ \\ = 6.25 \times {10}^{ - 2}$

6 0

3 years ago

Read 2 more answers

Two complementary angles are the ratio if 4:2 find the measure of each angle

strojnjashka [21]

Let the ratio be termed as 4x and 2x.
Now,
4x + 2x= 90
or,6x=90
or,x=90/6
or,x=15
So the measure of angles are,4x= 4×15
= .........
and,2x=2×15 =.....

6 0

3 years ago

A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0

2 years ago