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Viefleur [7K]
3 years ago
8

BRAINIEST TO WHOEVER RIGHT

Mathematics
1 answer:
ioda3 years ago
3 0

Answer:

The range of data is 1 ,that is from -9 to 6

75% of data lies between -9 and 3.5 or 4

The onterquartile value is -1.5

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In the given figure △ABC ≅△DEC. Which of the following relations can be proven using CPCTC ?
Serhud [2]

Option B:

\overline{A B}=\overline{D E}

Solution:

In the given figure \triangle A B C \cong \triangle D E C.

If two triangles are similar, then their corresponding sides and angles are equal.

By CPCTC, in \triangle A B C \ \text{and}\ \triangle D E C,

\overline{AB }=\overline{DE} – – – – (1)

\overline{B C}=\overline{EC} – – – – (2)

\overline{ CA}=\overline{CD} – – – – (3)

\angle ACB=\angle DCE  – – – – (4)

\angle ABC=\angle DEC  – – – – (5)

\angle BAC=\angle EDC  – – – – (6)

Option A: \overline{B C}=\overline{D C}

By CPCTC proved in equation (2) \overline{B C}=\overline{EC}.

Therefore \overline{B C}\neq \overline{D C}. Option A is false.

Option B: \overline{A B}=\overline{D E}

By CPCTC proved in equation (1) \overline{AB }=\overline{DE}.

Therefore Option B is true.

Option C: \angle A C B=\angle D E C

By CPCTC proved in equation (4) \angle ACB=\angle DCE.

Therefore \angle A C B\neq \angle D E C. Option C is false.

Option D: \angle A B C=\angle E D C

By CPCTC proved in equation (5) \angle ABC=\angle DEC.

Therefore \angle A B C\neq \angle E D C. Option D is false.

Hence Option B is the correct answer.

\Rightarrow\overline{A B}=\overline{D E}

5 0
3 years ago
Write 0.326 in two other ways.
Whitepunk [10]
0.326= 326/1000
0.326= 163/500
0.326= 32.6%
5 0
3 years ago
Read 2 more answers
Solve the equation 3/4x+3-2x = -1/4+1/2x+5
elena55 [62]
Hi there! The answer is x = -1

Let's solve this equation step by step!
\frac{3}{4} x + 3 - 2x = - \frac{1}{4} + \frac{1}{2} x + 5

First collect terms.
- 1 \frac{1}{4} x + 3 = \frac{1}{2} x + 4 \frac{3}{4}

Subtract (1/2)x from both sides.
- 1\frac{3}{4} x + 3 = 4 \frac{3}{4}

Subtract 3 from both sides.
- 1\frac{3}{4} x = 1 \frac{3}{4}

And finally divide by -1 3/4
x = \frac{7}{4} \div - \frac{7}{4} = \frac{7}{4} \times - \frac{4}{7} = - \frac{28}{28} = - 1
8 0
4 years ago
Read 2 more answers
Explain how comparan
Umnica [9.8K]
How to comparan? Not sure
5 0
3 years ago
Read 2 more answers
In the Sahara Desert one day it was 136oF. In the Gobi Desert a temperature of
coldgirl [10]

Answer: 186^{\circ}F

Step-by-step explanation:

Given : In the Sahara Desert one day it was 136°F.

In the Gobi Desert a temperature of  -50°F was recorded.

Clearly ,  136°F> -50°F

Then, the difference between these two temperatures will be :-

136^{\circ}F-(-50)^{\circ}F\\\\=(136+50)^{\circ}F\ \ [\because \text{Product two neagtive sign is positive]}\\\\=186^{\circ}F

Hence, the difference between these two temperatures = 186^{\circ}F

7 0
3 years ago
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