Answer:
Explanation:
Step 1. Determine the cell potential
<u> E°/V </u>
2×[Cr ⟶ Cr³⁺ + 3e⁻] 0.744 V
<u>3×[Cu²⁺ + 2e⁻ ⟶ Cu] </u> <u>0.3419 V
</u>
2Cr + 3Cu²⁺ ⟶ 3Cu + 2Cr³⁺ 1.086 V
Step 2. Calculate ΔG°
Answer:
a ) 1876.14 grams CaBr2
b ) 19.78 grams N2
sorry..i only have time to do the first two :)
Explanation:
Answer is "0.05 mol".
<em>Explanation;</em>
We can do calculation by using a simple formula as
n = m/M
Where, n is the number of moles of the substance (mol), m is the mass of the substance (g) and M is the molar mass of the substance (g/mol).
Here,
n = ?
m = 2.80 g
M = 56.08 g/mol
By substitution,
n = 2.80 g /56.08 g/mol
n = 0.0499 mol ≈ 0.05 mol
Answer: 2NH4Br(aq)+Pb(C2H302(aq)-------------------->
2NH4C2H3o2(aq) + PbBr2(s)
Explanation:
The net equation is :Pb2+ (aq)2Br (aq)---------------------->PbBr2(s)
the spectator ions NH4 +C2H3O2 are canceled
