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aliya0001 [1]
3 years ago
6

Balance the following equation and determine the coefficients in order

Chemistry
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

D 4,3,2

Explanation:

4 Co + 3 O2 ----> 2 Co2O3

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A sample of sugar (C12H22O11) contains 1.505 × 1023 molecules of sugar. How many moles of sugar are present in the sample?
saveliy_v [14]

Answer: Option (a) is correct.

Explanation:

Molecules of sugar given = 1.505 \times 10^{23}

According to Avogadro's number it is known that 1 mole contains 6.023 \times 10^{23}.

Therefore, calculate the moles of sugar present in the sample as follows.

   Number of moles =  \frac {1.505 \times 10^{23}}{6.023 \times 10^{23}}

           = 0.25 mol

Thus, the moles of sugar present in the sample is 0.25 mol.

6 0
3 years ago
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1.Calculate the frequency of a chemical shift at 1.25 ppm using a 400 MHz NMR spectrometer.A)1500 HzB)450 HzC)320 HzD)500 Hz
Advocard [28]

Answer:

D

Explanation:

Chemical shift is given as

Frequency/frequency of instrument

Let c = chemical shift

F = frequency

I = frequency of instrument

Chemical shift = frequency/frequency Instrument

1.25ppm = Frequency /400

We cross multiply to find frequency

Frequency = 400 x 1.25

Frequency = 500Hz

Option d is the answer since it is 500hz

6 0
3 years ago
The dissolving of a solid in a liquid occurs at the surface of the acid. True False
labwork [276]
The answer is true.....
7 0
3 years ago
How many grams of iron are needed to combine with 24.9 g of 0 to make Fe203?
Pavlova-9 [17]

Answer:

Explanation:

Here's where all that equation balancing is going to come into use. Since the main object of the question is not the equation, I'm just going to balance it and use it.

4Fe + 3O2 ====> 2Fe2O3

Step One

Find the number of mols of O2 in 24.9 grams of O2

1 mol O2 = 2*16 = 32 grams

x mol O2 = 24.9 grams               Cross multiply

32x = 24.9 * 1                               Divide by 32

x = 24.9/32

x = 0.778 moles of O2

Step Two

Type the findings under the balanced equations parts. Solve for the number of moles of Fe

4Fe + 3O2 ====> 2Fe2O3

x          0.778

Step Three

Set up the proportion

4/x = 3/0.778            Cross multiply

Step Four

Solve the proportion moles of Fe

4*0.778 = 3x              

3.112   =    3x                      Divide by 3

3.112/3 = 3x/3

x = 1.037 moles of Fe

Step Five

Find the mass of Fe

1 mol Fe = 56 grams

1.037 mol Fe = x            Cross Multiply

x = 56*1.037

x = 58.1 grams

4 0
3 years ago
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