Question

Find the equation of straight line passing through the points (a,0) and (0,b). If the point (1,1) lies on the equation, prove that
1/a + 1/b =1​

Answer 1

Answer:

step by step

Step-by-step explanation:

Line passing (a,0) (0,b)

slope = (y2 - y1) / (x2 - x1) = - b/a

pass (0,b), y interception: b

Line: y = -b/a * x + b  

pass(1,1) y=1, x=1

1 = -b/a + b  

1/b = (-b/a) /b + b/b

1/b = -1/a + 1

1/a + 1/b = 1  

Answer 2

Answer:

do the following

Step-by-step explanation:

the question says that the line is passing thur the point 1,1 ... so when x = 1 so does y ... also  when  x= a.. then y=0 and when y=b then x =0  .. and this is a straight line... also  1/a + 1/b = 1

if you were to draw on a graph... this .. you would see that when b=2  then x=0 and also when a=2.. then y = 0  ....

and 1/2 + 1/2 =1

so that's the line.... draw in just roughly.... you'll see... then what is the equation of that line.. usually we would use  the slope intercept formula for the equations.. there are more than one way to show the line.. is my point.. but.. if we use  y = mx + b  where m = -1   and b = 2 then...

y= - x+2

That answer got long.. sorry :/