Which of the following is a true statement?(1 point)

For the reaction 2 H 2 O ( g ) − ⇀ ↽ − 2 H 2 ( g ) + O 2 ( g ) the equilibrium concentrations were found to be [ H 2 O ] = 0.250

Bess [88]

Answer: The equilibrium constant for the given reaction is 4.224

Explanation:

We are given:

Equilibrium concentration of water = 0.250 M

Equilibrium concentration of hydrogen gas = 0.330 M

Equilibrium concentration of oxygen gas = 0.800 M

For the given chemical reaction:

$2H_2O(g)\rightleftharpoons H_2(g)+O_2(g)$

The expression of $K_{eq}$ for above reaction follows:

$K_{eq}=\frac{[H_2][O_2]}{[H_2O]^2}$

Putting values in above expression, we get:

$K_{eq}=\frac{0.330\times 0.800}{(0.250)^2}\\\\K_{eq}=4.224$

Hence, the equilibrium constant for the given reaction is 4.224

7 0

3 years ago

What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma

natta225 [31]

Answer : The empirical of the compound is, $C_1H_2O_3$

Solution : Given,

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 19.36 g

Mass of H = 3.25 g

Mass of O = 77.39 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{19.36g}{12g/mole}=1.613moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{3.25g}{1g/mole}=3.25moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{77.39g}{16g/mole}=4.837moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{1.613}{1.613}=1$

For H = $\frac{3.25}{1.613}=2.01\approx 2$

For o = $\frac{4.837}{1.613}=2.99\approx 3$

The ratio of C : H : O = 1 : 2 : 3

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = $C_1H_2O_3$

Therefore, the empirical of the compound is, $C_1H_2O_3$

6 0

3 years ago

Can someone check my work and tell me if I did it right

svlad2 [7]

Answer:

pretty sure u did it right??

3 0

3 years ago

Read 2 more answers

What's the formula for distance?

nekit [7.7K]

There are several formulas for distance. The one you choose to use is the one that expressed distance in terms of the information that you already have. For example, if you already know the speed and the time you've been traveling, then the formula for the distance you've covered is D = (speed) times (time) .

5 0

3 years ago

The density of ethanol is 0.789 g/mL. If you need 460.0 g of ethanol for an experiment, how many milliliters would you measure o

4vir4ik [10]

Answer:

The volume is 583.02 mL

Explanation:

Given that the density is:-

$\rho=0.789\ g/mL$