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Reptile [31]
3 years ago
5

A sample of oxygen gas has a volume of 45.8 mL when its pressure is 0.492 atm. What

Chemistry
2 answers:
kifflom [539]3 years ago
6 0
the answer should be 23.6
White raven [17]3 years ago
4 0

Answer:

<h2> a. 23.6</h2>

Explanation:

P_1=0.492\:atm\\V_1 = 45.8\:ml\\V_2 = ?\\P_1 = 0.954\:atm\\\\Boyle's Law = P_1V_1 = P_2V_2\\\\Lets \:make\: V \:subject\:of\:the\:formula\\\\\frac{P_1V_1}{P_2} = \frac{P_2V_2}{P_2} \\ \\V_2 =\frac{P_1V_1}{P_2} \\V_2 = \frac{0.492\times45.8}{0.954}\\ \\V_2 = \frac{22.5336}{0.954} \\\\V_2  = 23.620\\\\V_2 = 23.6

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Multiply everything on the top= 6.93 x 10^23
Divide by everything on the bottom = 6.93 x 10^23
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4 0
3 years ago
Read 2 more answers
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

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\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

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b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

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c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

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I hope it helps!

6 0
3 years ago
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8 0
3 years ago
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Answer:

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Explanation:

Hello!

In this case, considering that we are performing a conversion by which the time should be cancelled out to obtain liters, we first need to convert the seconds on bottom to hours and then the volume on top to liters, just a shown down below:

2.0\frac{mL}{s} *\frac{1L}{1000mL} *\frac{3600s}{1hr}*4.0hr\\\\=28.8L

Which turns out 29 L with 2 significant figures.

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