1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hram777 [196]
3 years ago
10

What dividend is represented by the synthetic division below?

Mathematics
2 answers:
eimsori [14]3 years ago
8 0

Answer:

the dividend is 2x^3 + 10x^2 + x + 5

Step-by-step explanation:

Oduvanchick [21]3 years ago
6 0

Answer:

the dividend is 2x^3 + 10x^2 + x + 5

Step-by-step explanation:

I took the test and I got a 100%

You might be interested in
If x = 4, y = 2 and z = 1 then xz (4y - 2z) is: 861, 24, 46, or 40. Help please.
dybincka [34]
(4)(1) * (4(2)-2(1))
4 * (8-2)
4*6
24
8 0
3 years ago
When working through limit problems, why must you write the limit statement every time until you evaluate the equation?
Softa [21]
Because that how it goes
8 0
3 years ago
Any suggestions or ideas
kirill115 [55]
That will be D good sir
4 0
3 years ago
Read 2 more answers
Calculate the hcf of 125​
scoundrel [369]

Answer:

factors of 125 are:

1, 5, 25, 125

I'm not sure what u mean..... if you want to find hcf of a value then there has to be two value example: hcf of 125 and 225

7 0
3 years ago
Read 2 more answers
T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


The given curve is y=7e^{x}


{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

Solving this we get

x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

k(x)=\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}

k(x)=\frac{7}{\infty}

k(x)=0







5 0
3 years ago
Other questions:
  • PLZ HELP!!!!<br><br> Solve for x.
    9·1 answer
  • If it costs $55,000 to put on a magic show for two weeks and the estimated revenue is $15,000 per night for 14 nights, what will
    8·2 answers
  • This building is one of the most identifiable structures in its city skylines. It has a square foundation and 28 floors. The bui
    13·1 answer
  • can someone help me. i am struggling to do this question. i need the other two boxes and thats it. please. who ever gets it righ
    8·1 answer
  • A4 Find length AC<br> idk how to do this someone help me
    11·2 answers
  • G(x) =x +5 then what is g(7)
    9·1 answer
  • Hallllllpppppp now
    7·1 answer
  • Can you help plz<br><br> EEEEEEEEEEEEEEEEEEEEEE
    6·2 answers
  • The total surface area of a cube is 1350sqcm find volume?​
    8·1 answer
  • A car used 1/32 of a gallon of gas to drive ¼ of a mile. At this rate, how many miles can the car travel using 1 gallon of gas?
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!