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2 answers:
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Answer:
Step-by-step explanation:
Given that tags are attached to the left and right hind legs of a cow in a pasture. Let A1 be the event that the left tag is lost and the event that the right leg tag is lost. Suppose those two events are independent and A2 the event that the right leg tag is lost. Suppose those two events are independent and P(A1) = P(A2) = 0.3
a) the probability that at least one leg tag is lost
=
(since A1 and A2 are independent)
=0.3+0.3-0.09
=0.51
b) the probability that exactly one tag is lost, given that at least one tag is lost.
= P(one leg lost)/P(atleast one leg lost)
=
c) the probability that exactly one tag is lost, given that at most one tag is lost.
Answer:
Approximately 313 cakes of similar size as those 50 cut from the smaller cake, can be cut from the bigger cake.
Step-by-step explanation:
The complete question is with the missing image of the cakes is attached to this solution.
From the image provided, the dimensions of the smaller cake = 2 ft × 1.6 ft
The dimensions of the larger cake = 5 ft × 4 ft
50 cakes are obtained from the smaller cake, how many cakes can be obtained from the bigger cake?
Area of the smaller cake = 2 × 1.6 = 3.2 ft²
Area of the bigger cake = 5 × 4 = 20 ft²
3.2 ft² cake provides 50 cakes.
20 ft² cake will provide (20×50/3.2) cakes = 312.5 cakes
Rounded to the nearest piece of cake = 313 cakes
Hope this Helps!!!
