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3 years ago

Quia Active 16:05:5 A plant root is an example of

Physics

2 answers:

pogonyaev3 years ago

7 0

Answer:A plant root is an example of an organ

Explanation:The main function of the root is to collect nutrients and water from the soil.

muminat3 years ago

5 0

Answer:

hi sorry i just want points YOSHIII :3

Explanation:

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Differences in ocean-surface height can be measured by _____.\

bonufazy [111]

<h3><u>Answer;</u></h3>

Satellite

Differences in ocean-surface height can be measured by<u> Satellite</u>

<h3><u>Explanation;</u></h3>

The topography of the ocean or the height of the ocean surface relative to a level of no motion provides the information on tides, and the distribution of heat and mass in the Earths's oceans.
<em><u>The ocean topography is measured using satellites altimeter. Satellites use radar altimeters that are specially made to measure the height of the ocean surface. The satellites measure the height of the ocean surface with an accuracy of 3 cm relative to the center of the earth.</u></em>
Satellite altimeter combines precise orbit determination with accurate ranging by a microwave altimeter of ocean distance to the satellite.

3 0

3 years ago

Read 2 more answers

A certain factory whistle can be heard up to a distance of 2.5 km. Assuming that the acoustic output of the whistle is uniform i

enyata [817]

Answer:

Emitted power will be equal to $7.85\times 10^{-5}watt$

Explanation:

It is given factory whistle can be heard up to a distance of R=2.5 km = 2500 m

Threshold of human hearing $I=10^{-12}W/m^2$

We have to find the emitted power

Emitted power is equal to $P=I\times A$

$P=I\times 4\pi R^2$

$P=10^{-12}\times 4\times 3.14\times 2500^2=7.85\times 10^{-5}watt$

So emitted power will be equal to $7.85\times 10^{-5}watt$

4 0

3 years ago

A circuit consists of a coil that has a self-inductance equal to 4.3 mH and an internal resistance equal to 16 Ω, an ideal 9 V b

fredd [130]

Answer:

t = 186.2 μs

Explanation:

Current in LR series circuit

$I(t) = I_{s}( 1 - e^{-Rt/L)}$ ----(1)

steady current = I_{s} = V/R

time constant = τ = $L/R =4.3 * 10^{-3} / 16\\$

= 0.268 ms

magnetic energy stored in coil = $U_{L} = \frac{1}{2}LI^{2}$

rate at which magnetic energy stored in coil= $\frac{d}{dt}U_{L} =\frac{d}{dt} \frac{1}{2}LI^{2} \\ = LI\frac{dI}{dt}\\$ ----(2)

rate at which power is dissipated in R:

$P = I^{2}R$ ---(3)

To find the time when the rate at which energy is dissipated in the coil equals the rate at which magnetic energy is stored in the coil equate (2) and (3)

$I^{2}R=LI \frac{dI}{dt}$