Answer:
false, that shouldn't be a a priority to identify if they are or not.
Explanation:
Answer:
0 times because front is not clear
A mixture can be composed of a few individual objects or several complex groups of objects.
Hope I helped! ( Smiles )
Answer:
In Python:
import os.path
from os import path
fname = input("Filename: ")
if path.exists(fname):
with open(fname) as file_in:
lines = []
for line in file_in:
lines.append(line.rstrip('\n'))
f = open("stat.txt","r+")
f.truncate(0)
f = open("stat.txt", "a")
f.write("Names\tTotal\tSubjects\tAverage\n")
for i in range(len(lines)):
rowsum = 0; count = 0
nm = lines[i].split()
for j in nm:
if (j.isdecimal()):
count+=1
rowsum+=int(j)
average = rowsum/count
f.write(nm[0]+"\t %3d\t %2d\t\t %.2f\n" % (rowsum, count, average))
f.close()
else:
print("File does not exist")
Explanation:
See attachment for explanation where comments were used to explain each line
Answer:
5) 3 0 0
Explanation:
Given data
int [] val = { 3, 10, 44 };
The total number of parameters of given array are 3, so total length of array is also 3.
The indexing of array starts with '0', Therefore the indexes of array with length zero are: {0,1,2}
The value of array at index 0 is = 3
similarly
value at index 1 = 10
value at index 2 = 44
Here, Int i = 1 is storing the value '1' in integer variable i.
In addition to that, any value of index 'i' of an array is selected using array[i].
Therefore,
val[i] = i-1 is copying the value (i-1 = 1-1 = 0) to the index '1' of the array because i = 1.
So value at index 1 would be = val[1] = 0
The term i++ is incrementing the value of i, it makes i =2
val[i] = i-1 is copying the value (i-1 = 1-1 = 0) to the index '2' of the array because i = 2 now.
So value at index 2 would be = val[2] = 0
Hence, the output would be {3 0 0}. So 5th option is correct.
