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3 years ago

Which of these is not an application software?

Computers and Technology

2 answers:

yuradex [85]3 years ago

7 0

Answer:

D. utilities should be the answer

fredd [130]3 years ago

6 0

A; control and measurment

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How can photography allow us to view the world around us in different ways?

Ymorist [56]

It captures a single moment that one might not see with a naked eye. It shows the beauty and the essence of simple things in one exact moment. And it allows the viewer to take more time to reflect on what is captured and really find meaning within it.

6 0

3 years ago

Read 2 more answers

he function below takes one parameter: a list of strings (string_list). Complete the function to return a new list containing on

Aleks04 [339]

Answer:

def select_short_strings(string_list):

new_list = []

for s in string_list:

if len(s) < 20:

new_list.append(s)

return new_list

lst = ["apple", "I am learning Python and it is fun!", "I love programming, it is easy", "orange"]

print(select_short_strings(lst))

Explanation:

- Create a function called select_short_strings that takes one argument string_list

Inside the function:

- Initialize an empty list to hold the strings that are less than 20

- Inside the loop, check the strings inside string_list has a length that is smaller than 20. If found one, put it to the new_list.

- When the loop is done, return the new_list

- Create a list to check and call the function

4 0

3 years ago

Read 2 more answers

How many possible password of length four to eight symbols can be formed using English alphabets both upper and lower case (A-Z

Fynjy0 [20]

Answer:

In a password, symbol/characters can be repeated. first calculate the total

symbols which can be used in a password.

So there are total 26(A-Z),26(a-z),10(0-9) and 2(_,$) symbols.

that is equal to 26+26+10+2=64.

Total number of password of length 4:

here at each place can filled in total number of symbols i.e 64 way for each

place.Then total number of possible password is:

64*64*64*64=16777216

Total number of password of length 5:

here at each place can filled in total number of symbols i.e 64 way for each

place.Then total number of possible password is:

64*64*64*64*64=1073741824

Similarly,

Total number of password of length 6:

64*64*64*64*64*64=68719476736

Total number of password of length 7:

64*64*64*64*64*64*64=4398046511104

Total number of password of length 8:

64*64*64*64*64*64*64=281474976710656

Hence the total number of password possible is:285,942,833,217,536

7 0

4 years ago

Sketch a 2K x 32 memory built from 1K x 8 memory chips. Include control, address, and data line details, as well as any decoding

Scrat [10]

Answer:

See my explanations and attachment

Explanation:

Construct an 8k X 32 ROM using 2k X 8 ROM chips and any additional required components. Show how the address and data lines of the constructed 8k X 32 ROM are connected to the 2k X 8 chips.

I tried to solve it but I am not sure if I got the correct answer. Could anyone check my drawing and correct me?

8 0

3 years ago

Given two 2x3 (2 rows, 3 columns) arrays of integer , x1 and x2, both already initialized , two integer variables , i and j, and

Gnesinka [82]

JAVA programming was employed...

What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules

Solution:

for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x1[i][j] = num.nextInt();
}
}// End of Array 1, x1.

for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x2[i][j] = num.nextInt();
}
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:

x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
x1rules = true;
system.out.print(x1rules);
}
else
{
system.out.print(x1rules);
}//Conditional Statement

7 0

3 years ago