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Vitek1552 [10]
3 years ago
13

Name the following aromatic hydrocarbon:

Chemistry
1 answer:
irina1246 [14]3 years ago
8 0

Explanation:

I think option 3..............

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DESCRIBE THE FINAL TEMPERATURE AFTER DIFFUSION
frez [133]

Answer:

Simple Diffusion

In basic terms, diffusion can be defined as the process by which particles spread out. This is generally from an area where they are high in concentration to an area where they are in a lower concentration. This can be understood by thinking of a pan with onions cooking in it. The smell given off by the onions is very concentrated in the top of the pan, above the cooking onions. The molecules, therefore, move into an area when they are in lower concentration, such as the surrounding air. Eventually, the smell spreads throughout the kitchen or even the entire home.

Mixing Diffusion

If two different gases or liquids are close to each other, the process of diffusion causes them to mix together. Imagine two gases separated by a partition. The free-moving gas molecules bounce off the central partition as they whirl around in their container. If the partition is removed, the gases mix as the molecules move around. This is related to the second law of thermodynamics, which states that in a closed system, all things tend toward entropy. “Entropy,” for this purpose, can simply be defined as disorder; therefore, unmixed particles in a closed system tend to mix, or diffuse.

8 0
3 years ago
There are five objects (a pink object, a yellow object, a white object, a gray object, and a violet object). Each object has a d
Serggg [28]
I- what is wrong with teachers???
3 0
3 years ago
In a classroom which comparison would a teacher most likely use for describing a mole
irina [24]
Mole - one of the most important concepts in chemistry - is a kind of link to go from the microworld of atoms and molecules in a normal macrocosm grams and kilograms.
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3 0
4 years ago
A container is filled to a volume of 55.2 L at 61 °C. While keeping the
babymother [125]

Answer:

4.45 atm

Explanation:

Applying,

PV = P'V'............ Equation 1

Where P = Initial pressure of the container, V = Initial volume of the container, P' = Final pressure of the container, V' = Final volume of the container.

make P the subject of the equation

P = P'V'/V........... Equation 2

From the question,

Given: V = 55.2 L, P' = 8.53 atm, V' = 28.8 L

Substitute these values into equation 2

P = (8.53×28.8)/55.2

P = 4.45 atm

5 0
4 years ago
Read 2 more answers
2CO2 + 3H2O + 4Br2<br><br> C = <br><br> O = <br><br> H = <br><br> Br =
devlian [24]

Explanation:

2CO2 + 3H2O + 4Br2

C = 2

O = 5

H = 6

Br =8

8 0
3 years ago
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