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inessss [21]
3 years ago
8

What creates an ionic bond?

Chemistry
1 answer:
Anna71 [15]3 years ago
6 0

Answer:c

Explanation: it’s c

You might be interested in
3) a) (2 points) Label the 1H NMR spectrum of adipic acid by identifying key resonances. Use letters (a, b, c, etc.) to match Hs
Bess [88]

Answer:

The label of spectrum is attached.

Explanation:

adipic acid is equal to:

COOH - CH2 - CH2 - CH2 - CH2 - COOH

(1)            (2)      (3)       (3)       (2)       (1)

The structure of adipic acid indicates that it has 3 equivalent carbons, therefore it should have 3 peaks in the spectrum:

The first peak at approximately 172 ppm is from carbon (1) COOH. The second peak is at approximately 23 ppm and is by carbon number (3) CH2. and the third peak is at approximately 37 ppm and is due to group number (2) CH2.

3 0
3 years ago
Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, , with methanol, . In an experiment, 1.60 g of sal
bekas [8.4K]

Answer:

90.71%

Explanation:

From the equation of reaction:

C_7H_6O_3 + CH_4O --> C_8H_8O_3

1 mole of salicylic acid requires 1 mole of methanol in order to produce 1 mole of methyl salicylate.

<em>mole = mass/molar mass</em>

1.6 g of salicylic acid = 1.6/138.121 = 0.012 moles

15 g of methanol = 15/32.04 = 0.47 moles

<em>Salicylic acid is the limiting reagent and hence, 0.012 moles of methyl salicylate would be produced according to the mole ratio above.</em>

0.012 moles of methyl salicylate = 0.012 x 152.1494 = 1.83 g

The theoretical yield of methyl salicylate is 1.83 g while the actual yield is 1.66 g.

<em>Percentage yield = actual yield/theoretical yield x 100%</em>

                         1.66/1.83 x 100% = 90.71%

7 0
3 years ago
Will a precipitate form if you mix 75.0 mL of a NaOH solution with pOH of 2.58 if it is mixed with 125.0 mL of a 0.0018 M MgCl2
r-ruslan [8.4K]

A precipiatate of mass 0.013 g is formed when you mix 75.0 mL of a NaOH solution with pOH of 2.58 and  125.0 mL of a 0.0018 M MgCl2 solution

<h3>What is stoichiometry?</h3>

In stoichiometry, calculations are made based on mass - mole or mole - volume relationships. First we must put down the balanced reaction equation; 2NaOH(aq) + MgCl2(aq) -----> Mg(OH)2(s) + 2NaCl(aq)

Now Ionically;

2OH^-(aq) + Mg^2+(aq)  -----> Mg(OH)2(s)

Concentration of OH^- = Antilog (-2.58) = 2.6 * 10^-3 M

Number of moles of OH^- = 2.6 * 10^-3 M * 75/1000 = 0.000195 moles

Concentration of Mg^2+ = 0.0018 M

Number of moles of Mg^2+ =0.0018 M * 125/1000 = 0.000225 moles

Since;

1 mole of Mg^2+ reacts with 2 moles of  OH^-

x moles of Mg^2+ reacts with 0.000195 moles of  OH^-

x = 0.0000975 moles

Mg^2+  is the limiting reactant.

1 mole of Mg^2+ yields 1 mole of the precipitate

0.000225 moles of Mg^2+ yields 0.000225 moles of precipitate.

Hence, a precipitate is formed.

Learn more about precipitate: brainly.com/question/1770619?

5 0
3 years ago
According to most scientists, cold fusion
Anton [14]

will not be a practical source of energy on Earth

3 0
3 years ago
Read 2 more answers
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.02 g of ethane is
miv72 [106K]

Answer:

3.13g

Explanation:

First, we'll begin by writing a balanced equation between the reaction of gaseous ethane with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. This is illustrated below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Next, let us calculate the mass of C2H6 and the mass of O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H6 = (12x2) + (6x1) = 24 + 6 = 30g/mol

The mass of C2H6 that reacted from the balanced equation = 2 x 30 = 60g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 that reacted from the balanced equation = 7 x 32 = 224g

Now, to calculate the left over mass of ethane (C2H6), let us first calculate the mass of ethane (C2H6) that will react with 22g of oxygen(O2). This can be achieved by doing the following:

From the balanced equation above,

60g of C2H6 reacted with 224g of O2.

Therefore, Xg of C2H6 will react with 22g of O2 i.e

Xg of C2H6 = (60 x 22)/224

Xg of C2H6 = 5.89g

From the calculations above, 5.89g will react completely with 22g of O2.

The left over mass of C2H6 can be obtained as follow:

Mass of C2H6 from the question = 9.02g

Mass of C2H6 that reacted = 5.89g

The left over mass of C2H6 =?

The left over mass of C2H6 = Mass of C2H6 - mass of C2H6 that reacted

Left over mass of C2H6 = 9.02 - 5.89

Left over mass of C2H6 = 3.13g

7 0
4 years ago
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