The result when the OH- ions go as additional acid is added is that t<span>hey remain in solution but change concentration. </span>This is because when you add more acid to hydroxide, it will change its concentration due to the acidity added.
4. density, temperature, surface tension.
7. extensive properties- uses mass and volume depends on tbe amount of substance present.
Periodic table is an arrangement of chemical elements in an organized manner with atomic number. Elements are distributed in columns and groups in periodic table according to their properties.
Many elements have their isotopes and mostly are radioactive but isotopes are not mentioned on the periodic table, elements are mentioned there and all trans-uranium elements are most radioactive.
Answer:
Explanation:
In this problem we only have information of the equilibrium, so we need to find a expression of the free energy in function of the constant of equilireium (Keq):
Being Keq:
![K_{eq}=\frac{[fructose][Pi]}{[Fructose-1-P]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5Bfructose%5D%5BPi%5D%7D%7B%5BFructose-1-P%5D%7D)
Initial conditions:
![[Fructose-1-P]=0.2M](https://tex.z-dn.net/?f=%5BFructose-1-P%5D%3D0.2M)
![[Fructose]=0M](https://tex.z-dn.net/?f=%5BFructose%5D%3D0M)
![[Pi]=0M](https://tex.z-dn.net/?f=%5BPi%5D%3D0M)
Equilibrium conditions:
![[Fructose-1-P]=6.52*10^{-5}M](https://tex.z-dn.net/?f=%5BFructose-1-P%5D%3D6.52%2A10%5E%7B-5%7DM)
![[Fructose]=0.2M-6.52*10^{-5}M](https://tex.z-dn.net/?f=%5BFructose%5D%3D0.2M-6.52%2A10%5E%7B-5%7DM)
![[Pi]=0.2M-6.52*10^{-5}M](https://tex.z-dn.net/?f=%5BPi%5D%3D0.2M-6.52%2A10%5E%7B-5%7DM)
Free-energy for T=298K (standard):
