What creates an ionic bond?

Which conditions are necessary for natural selection? Check all that apply. Populations do not have genetic variation. Populatio

igor_vitrenko [27]

Answer:

Populations have genetic variation.

The environment changes.

Organisms must have specific traits in order to survive and reproduce.

Explanation:

Natural selection is a phenomenon whereby organisms better adapted to their environment are able to survive due to this phenotypic capability.

Natural selection provides an advantage during an adverse condition for organisms that have a rich genetic variation in their population.
Also, environmental changes induces natural selection whereby organisms must adapt to changes around.
For organisms to survive, they must have specific traits that gives them a competitive reproductive advantage.

7 0

3 years ago

Read 2 more answers

t 745 K, the reaction below has an equilibrium constant (Kc) of 5.00 × 102. H2 (g) + I2 (g) ⇌ 2 HI (g) If a mixture of 0.10 mol

spayn [35]

Answer : The concentration of HI (g) at equilibrium is, 0.643 M

Explanation :

The given chemical reaction is:

$H_2(g)+I_2(g)\rightarrow 2HI(g)$

Initial conc. 0.10 0.10 0.50

At eqm. (0.10-x) (0.10-x) (0.50+2x)

As we are given:

$K_c=5.00\times 10^2$

The expression for equilibrium constant is:

$K_c=\frac{[HI]^2}{[H_2][I_2]}$

Now put all the given values in this expression, we get:

$5.00\times 10^2=\frac{(0.50+2x)^2}{(0.10-x)\times (0.10-x)}$

x = 0.0713 and x = 0.134

We are neglecting value of x = 0.134 because the equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.0713

The concentration of HI (g) at equilibrium = (0.50+2x) = [0.50+2(0.0713)] = 0.643 M

Thus, the concentration of HI (g) at equilibrium is, 0.643 M

8 0

4 years ago

Help i just need some help with thos

Alona [7]

Okay give me a few minutes and I will send u a screen shot of my answers.

5 0

3 years ago

If you have 5 unknowns and they were secondary alcohol aldehyde, carboxylic acid, amine, and alkane Put plan to identify the unk

Finger [1]

Answer:

the unknowns

Explanation:

7 0

3 years ago

Classify the following alcohol as primary,

Nata [24]

The classification of the alcohols gives;

Compound 1 - Primary alcohol
Compound 2 - Tertiary alcohol
Compound 3 - Secondary alcohol
Compound 4 - Secondary alcohol

<h3>What are alcohols?</h3>

Organic compounds occurs in families. The family of compounds is called a homologous series. The homologous series always have a functional group. The functional group is the atom, group of atoms or bond that is responsible for the chemical reactivity of the members of a given homologous series.

Now we know that the alcohols are those organic compounds that contains the -OH group. The could be aliphatic or alicyclic compounds. We shall now proceed to name the kind of alcohols that each of the compounds shown are;

Compound 1 - Primary alcohol
Compound 2 - Tertiary alcohol
Compound 3 - Secondary alcohol
Compound 4 - Secondary alcohol

Learn ore about alcohols:brainly.com/question/4698220

#SPJ1

3 0

2 years ago