Answer:
The probability of the combination {H, T and H} is 0.125.
Step-by-step explanation:
The sample space of flipping a quarter is:
S = {H and T}
The probability of both outcomes is same, i.e. P (H) = P (T) = 0.50.
It is provided that three quarters are flipped one at a time.
The outcomes of all the three quarters are independent of each other.
Compute the probability of the combination {H, T and H} as follows:
![P(\text{H},\text{T and H}) = P(\text{H})\times P(\text{T})\times P(\text{H})](https://tex.z-dn.net/?f=P%28%5Ctext%7BH%7D%2C%5Ctext%7BT%20and%20H%7D%29%20%3D%20P%28%5Ctext%7BH%7D%29%5Ctimes%20P%28%5Ctext%7BT%7D%29%5Ctimes%20P%28%5Ctext%7BH%7D%29)
![=0.50\times 0.50\times 0.50\\=0.125](https://tex.z-dn.net/?f=%3D0.50%5Ctimes%200.50%5Ctimes%200.50%5C%5C%3D0.125)
Thus, the probability of the combination {H, T and H} is 0.125.
Answer:
i think both of them cant be
The exterior angle is supplementary to the adjacent angle (they form a linear pair) and is the sum of the two angles in the triangle that are not adjacent to it. For example, in number 2, the exterior angle is 28+40=68 degrees. You can use the other method to check. 68 degrees is supposed to be in a linear pair with 112 degrees, which it is. So the answer to number 2 would be 68 degrees.
Try doing this for the rest of them
Answer:
b
Step-by-step explanation: