Increasing your workload a little bit is called?

As the car moves from point A , to point B, and finally to point C, the total energy of the car

Minchanka [31]

Answer: C

Explanation:

Energy stays the same, but there’s more kinetic energy the less it moves and mor kinetic energy the more it moves

3 0

3 years ago

From the top of a cliff, a person uses a slingshot to fire a pebble straight downward, which is the negative direction. The init

In-s [12.5K]

Answer:

a) the acceleration is -9.8 m/s^2 (gravity's acceleration), the magnitude is 9.8 m/s^2 and the direction is downwards.

The pebble is not decelerating since the magnitude of it's speed is increasing, even if it is on a negative direction.

b) after 0.5 s the pebble is 5.725 meters down. (or -5.725m from it's initial position.)

Explanation:

a) the acceleration is given only by gravity, it's the only force acting on the pebble, the slingshot only gives the pebble an initial speed.

b) To calculate the position we use the equation

y0 + v0·t + ½·g·t² = yf

replacing:

0 + (-9.0m/s) * 0.5s + 1/2 (-9.8)*0.5² = yf

-5.725 = yf

7 0

4 years ago

6) 100 ml of water is initially at 20°C. 30,000 J of heat is added to the water. What is temperature change for the water?

vovangra [49]

The temperature change of water is equal to 71.67 °C

<h3>Explanation:</h3>

Given:

Amount of transferred energy = 30,000 K J

Mass of water = 100 ml

Initial temperature = 20°C

To find the change in temperature of water.

Formula for Heat capacity is given by

Q = m×c×Δt ........................................(1)

where:

Q = Heat capacity of the substance (in J)

m=mass of the substance being heated in grams(g)

c = the specific heat of the substance in J/(g.°C)

Δt = Change in temperature (in °C)

Δt = (Final temperature - Initial temperature) = T(f) - T(i)

Q = 30,000 J

Mass of water = m = 100 ml

1 ml = 1 g ................................................(2)

Therefore m = 100 ml = 100 g

Specific heat of water is c = 4.186 J /g.

Δt = ?

Substituting these in equation (1), we get

Q = m×c×Δt

Rearranging the terms for Δt,

Δt = $\frac{Q}{m\times c}$

Δt = $\frac{30,000}{100\times 4.186} = \frac{30,000}{418.6}= 71.67\°C$

Δt = 71.67 °C

8 0

4 years ago

Compared to the buoyant force of the atmosphere on a 1-kilogram helium-filled balloon, the buoyant force of the atmosphere on a

Vladimir [108]

It all depends on the SIZE of the balloon.

If the balloon is made of really tough rubber, and it holds the helium in the same volume as the solid iron block, then the buoyant force of the atmosphere is the same for both objects.

But if the balloon is just some flimsy stuff, and it lets the helium expand to a much bigger volume than the iron block, then the buoyant force on the balloon is greater than the buoyant force on the solid iron block.

In fact, it DOESN'T MATTER what's in the balloon and what's in the block. It doesn't matter whether either one of them is solid, liquid, or gas, and it doesn't matter whether they have the same or different mass.

Whichever one has greater VOLUME has a greater buoyant force of atmosphere acting on it.

6 0

4 years ago

Read 2 more answers

What is the effect of the following change on the volume of 1 mol of an ideal gas? The initial pressure is 722 torr, the final p

Ray Of Light [21]

Answer:

A. Volume is unchanged

Explanation:

$P_{i}$ = initial pressure of the gas = 722 torr = 96258.7 pa