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3 years ago

A resistor is something placed in a circuit that totally blocks the flow of electrons.

Physics

2 answers:

xenn [34]3 years ago

6 0

False. It reduces flow. Does not completely stop the electron flow

Ipatiy [6.2K]3 years ago

6 0

Answer:

false

Explanation:

A resistor only reduces or regularizes the flow of current, not stop it totally.

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The distance between two planets is 1600 km. How much time would the light

Snowcat [4.5K]

Answer:

5.33*10^-3 seconds

Explanation:

c = d/t

c = speed of light constant (3.0*10^5 km/s)

d = distance (1600 km)

t = ?

3.0*10^5 = 1600/t

t = 1600/3.0*10^5

t = 5.33*10^-3 seconds

I hope this helped! :)

6 0

3 years ago

I need an answer to question number 4 ASAP

Nat2105 [25]

Answer:

Screwing

Explanation:

3 0

4 years ago

Help mee plss its very urgent i need this before 11 pm est

dmitriy555 [2]

Answer:

7. 2 kg

8. 0.5 kg

9. 4 kg

Explanation:

The equation is F=MA

where F is force in Newtons

M is mass in kg

A is acceleration in m/s^2

for each you substitute in the F and A, and you are finding M. Meaning you divide F by A.

M = F/A

6/3 = 2

6/12 = 0.5

20/5 = 4

6 0

3 years ago

Read 2 more answers

A 1-kg discus is thrown with a vertical velocity of 19 m/s at an angle of 35 degrees from a height of 1.94 m. Do not factor in a

Travka [436]

Answer:

Vertical velocity $V_y = 10.89 \ m/s$

Horizontal velocity $V_x = 15.57 \ m/s$

Explanation:

If a 1 -kg is thrown vertically with a velocity of 19 m/s at an angle of 35 °C from a height 1.94 m

The vertical and horizontal component can be resolved as:

$V_y = Vsin \theta \\ \\ \\\\V_x = Vcos \theta$

For Vertical component :

$V_y = V sin \theta \\\\V_y = 19 * sin 35 \\ \\ V_y = 19* 0..5736 \\ \\ V_y = 10.89 \ m/s$

For horizontal velocity

$V_x = V cos \theta \\\\V_x = 19 * cos 35 \\ \\ V_x = 19* 0.8192 \\ \\ V_x = 15.57 \ m/s$

4 0

3 years ago

Holly puts a box into the trunk of her car. Later, she drives around an unbanked curve that has a radius of 48 m. The speed of t

Troyanec [42]

Answer:

The minimum coefficient of static friction for the box on the floor of the trunk is 0.54.

Explanation:

Given that,

Radius of the unbanked curve, r = 48 m

The speed of the car on the curve, v = 16 m/s

We need to find the minimum coefficient of static friction for the box on the floor of the trunk. It can be calculated by balancing the centripetal force and the force of gravity as :

$\mu mg=\dfrac{mv^2}{r}$

$\mu=\dfrac{v^2}{rg}$

$\mu=\dfrac{(16)^2}{48\times 9.8}$

$\mu=0.54$

So, the minimum coefficient of static friction for the box on the floor of the trunk is 0.54. Hence, this is the required solution.

5 0

4 years ago