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Masteriza [31]
3 years ago
14

Compared to the buoyant force of the atmosphere on a 1-kilogram helium-filled balloon, the buoyant force of the atmosphere on a

nearby 1-kilogram solid iron block is _____.
Physics
2 answers:
bezimeni [28]3 years ago
7 0

Answer:

Explanation:

The buoyant force depends on the volume of the body

Buoyant force = Volume immersed x density of fluid x gravity

So, the density of fluid that means air is same for both the cases, but the volume of 1 kg helium balloon is more than the density of iron, so the buoyant force on helium is more than the buoyant force on iron.

Vladimir [108]3 years ago
6 0

It all depends on the SIZE of the balloon.

If the balloon is made of really tough rubber, and it holds the helium in the same volume as the solid iron block, then the buoyant force of the atmosphere is the same for both objects.

But if the balloon is just some flimsy stuff, and it lets the helium expand to a much bigger volume than the iron block, then the buoyant force on the balloon is greater than the buoyant force on the solid iron block.

In fact, it DOESN'T MATTER what's in the balloon and what's in the block.  It doesn't matter whether either one of them is solid, liquid, or gas, and it doesn't matter whether they have the same or different mass.  

Whichever one has greater VOLUME has a greater buoyant force of atmosphere acting on it.

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A gas bottle contains 0.250 mol of gas at 730 mm hg pressure. if the final pressure is 1.15 atm, how many moles of gas were adde
Ludmilka [50]

Answer: 0.049 mol



Explanation:



1) Data:


n₁ = 0.250 mol

p₁ = 730 mmHg

p₂ = 1.15 atm

n₂ - n₁ = ?


2) Assumptions:


i) ideal gas equation: pV = nRT


ii) V and T constants.


3) Solution:


i) Since the temperature and the volume must be assumed constant, you can simplify the ideal gas equation into:


pV = nRT ⇒ p/n = RT/V ⇒ p/n = constant.


ii) Then p₁ / n₁ = p₂ / n₂


⇒ n₂ = p₂ n₁ / p₁


iii) n₂ = 1.15atm × 760 mmHg/atm × 0.250 mol / 730mmHg = 0.299 mol


iv) n₂ - n₁ = 0.299 mol - 0.250 mol = 0.049 mol

7 0
3 years ago
Two cars A and B are 100m apart moving towards each other with
maxonik [38]

Let car A's starting position be the origin, so that its position at time <em>t</em> is

A: <em>x</em> = (40 m/s) <em>t</em>

and car B has position at time <em>t</em> of

B: <em>x</em> = 100 m - (60 m/s) <em>t</em>

<em />

They meet when their positions are equal:

(40 m/s) <em>t</em> = 100 m - (60 m/s) <em>t</em>

(100 m/s) <em>t</em> = 100 m

<em>t</em> = (100 m) / (100 m/s) = 1 s

so the cars meet 1 second after they start moving.

They are 100 m apart when the difference in their positions is equal to 100 m:

(40 m/s) <em>t</em> - (100 m - (60 m/s) <em>t</em>) = 100 m

(subtract car B's position from car A's position because we take car A's direction to be positive)

(100 m/s) <em>t</em> = 200 m

<em>t</em> = (200 m) / (100 m/s) = 2 s

so the cars are 100 m apart after 2 seconds.

3 0
3 years ago
A(n) 131 g ball is dropped from a height
larisa [96]

Answer:

26.59 N/m

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 131 g

Extention (e) = 4.82755 cm

Acceleration due to gravity (g) = 9.8 m/s²

Spring constant (K) =?

Next, we shall convert 131 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

131 g = 131 g × 1 Kg / 1000 g

131 g = 0.131 Kg

Thus, 131 g is equivalent to 0.131 Kg.

Next, we shall the force exerted by the ball on the spring. This can be obtained as follow:

Mass (m) = 0.131 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = ma

F = 0.131 × 9.8

F = 1.2838 N

Next, we shall convert 4.82755 cm to metre (m)

This can be obtained as follow:

100 cm = 1 m

Therefore,

4.82755 cm = 4.82755 cm × 1 m / 100 cm

4.82755 cm = 0.0482755 m

Thus, 4.82755 cm is equivalent to 0.0482755 m

Finally, we shall determine the spring constant as follow:

Force (F) = 1.2838 N

Extention (e) = 0.0482755 m

Spring constant (K) =?

F = Ke

1.2838 = K × 0.0482755

Divide both side by 0.0482755

K = 1.2838 / 0.0482755

K = 26.59 N/m

Thus the spring constant is 26.59 N/m

7 0
3 years ago
Which balloon would fall faster, water filled or murcury filled?
bazaltina [42]
A mercury filled balloon would fall faster then water. Mercury is heavier.
7 0
3 years ago
2. Which of the following wavelength properties would require a stopwatch to measure?
katovenus [111]

Answer:

<u><em>A. wavelength</em></u>

Explanation:

The others are about sound and how high it is. That has nothing to do with time.

3 0
3 years ago
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