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Masteriza [31]
4 years ago
14

Compared to the buoyant force of the atmosphere on a 1-kilogram helium-filled balloon, the buoyant force of the atmosphere on a

nearby 1-kilogram solid iron block is _____.
Physics
2 answers:
bezimeni [28]4 years ago
7 0

Answer:

Explanation:

The buoyant force depends on the volume of the body

Buoyant force = Volume immersed x density of fluid x gravity

So, the density of fluid that means air is same for both the cases, but the volume of 1 kg helium balloon is more than the density of iron, so the buoyant force on helium is more than the buoyant force on iron.

Vladimir [108]4 years ago
6 0

It all depends on the SIZE of the balloon.

If the balloon is made of really tough rubber, and it holds the helium in the same volume as the solid iron block, then the buoyant force of the atmosphere is the same for both objects.

But if the balloon is just some flimsy stuff, and it lets the helium expand to a much bigger volume than the iron block, then the buoyant force on the balloon is greater than the buoyant force on the solid iron block.

In fact, it DOESN'T MATTER what's in the balloon and what's in the block.  It doesn't matter whether either one of them is solid, liquid, or gas, and it doesn't matter whether they have the same or different mass.  

Whichever one has greater VOLUME has a greater buoyant force of atmosphere acting on it.

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Ksenya-84 [330]

Answer: Use this F=Ma.

Explanation: So your answer will be

F=1 Kg+9.8 ms-2

So the answer will be

F=9.8N

How'd I do this?

I just used Newton's second law of motion.

I'll also put the derivation just in case.

Applied force α (Not its alpha, proportionality symbol) change in momentum

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or then

F α m(v-u)/t

So, as we know v=final velocity & u= initial velocity and v-u/t =a.

So F α ma, we now remove the proportionality symbol so we'll add a proportionality constant to make the RHS & LHS equal.

So, F=<em>k</em>ma (where k is the proportionality constant)

<em>k</em> is 1 so you can ignore it.

So, our equation becomes F=ma

7 0
3 years ago
The molar enthalpy of fusion for water is 6.008 kj/mol. what quantity of energy is released when 253g of liquid water freezes? (
e-lub [12.9K]
During freezing, energy is released by the mass of water without change in temperature. Such energy will also be required if the same mass of water has to be melted.

Then,

Number of moles = mass/molar mass = 253/18.02 =14.04 moles

Energy released = moles*molar enthalpy of fusion = 14.04*6.008 = 84.35 kJ
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3 years ago
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Tomtit [17]

Answer:

<u>Toxicity is a quantitative property</u>

Explanation:

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<u />

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B. 0.6 for show
hopefully this works lemme know



4 0
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