Explanation:
Given that,
Weight = 280 lbs
Height = 60 ft
Power = 3.50 hp
(a). We need to calculate the work done by the boom on the fireman
Using formula of work done


Put the value into the formula




The work done by the boom is 21.59 Btu.
(b). We know that,
1 hp = 550 ft lbf
So, 

We need to calculate the time
Using formula of time

Put the value into the formula


The time is 8.7 sec.
Hence, This is the required solution.
Answer:
a) a = 2.35 m/s^2
Explanation:
(a) In order to calculate the magnitude of the acceleration of the ball, you use the following formula, for the position of the ball:
(1)
x: position of the ball after t seconds = 87 m
t: time = 8.6 s
a: acceleration of the ball = ?
vo: initial velocity of the ball = 0 m/s
You solve the equation (1) for a:

You replace the values of the parameters in the previous equation:

The acceleration of the ball is 2.35 m/s^2
Answer:
I would say false
Explanation:
Because friction slows it down which means when the object bounces back it will not have the same energy or force that was applied before.
E=the sound waves from the trombones have slightly different velocity
Both valves are closed during the power stroke.
While the fuel is burning in the cylinder, you want
all the force of the expanding gases to push the
piston down ... you don't want any of the gases
or their pressure escaping.
If either of the valves was open, even just a crack,
then part of the gases would go blooey out the valve,
and some pressure would be lost that's supposed to be
pushing the piston.