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SpyIntel [72]
3 years ago
6

A child and a sled with a combined mass of 50.0 kg slide down a frictionless slope. If the sled starts from rest and has a speed

of 3.00 m/s at the bottom, what is the height of the hill?
Physics
1 answer:
Mama L [17]3 years ago
3 0

Answer:

The height of the hill is 0.46 m.

Explanation:

Given;

mass of the child and sled, m = 50 kg

initial velocity of the sled, u = 0

final velocity of the sled, v = 3 m/s

The height of the high is calculated from the law of conservation of energy;

P.E at top = K.E at bottom

mgh = ¹/₂mv²

gh = ¹/₂v²

h = \frac{v^2}{2g} \\\\h = \frac{3^2}{2\times 9.8} \\\\h = 0.46 \ m

Therefore, the height of the hill is 0.46 m.

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A thin uniform cylindrical turntable of radius 2.3 m and mass 22 kg rotates in a horizontal plane with an initial angular speed
Svetllana [295]

Answer:

ω = 5.5 rad/s

Explanation:

  • Assuming no external torques present during the instant that the clump of clay is dropped on the turntable, total angular momentum must be conserved.
  • The angular momentum of a rotating rigid body, can be expressed as follows:

       L = I * \omega (1)

       where I = moment of inertia regarding the axis of rotation, and ω =

       angular speed of the rotating body.

  • Since the angular momentum must keep constant, this means that it must be satisfied the following equality:

       L_{o} = L_{f}  (2)

       where L₀ = I₀ * ω₀,  Lf = If * ωf.

       I₀ is the moment of inertia of a solid disk rotating around an axis

       passing through its center, as follows:

      I_{o} =\frac{1}{2} * m* r^{2}  = \frac{1}{2} * 22 kg*(2.3m)^{2} = 58.2 kgm2  (3)

      If, is the moment of inertia after dropping the clump of clay, which adds

      its own moment of inertia as a point mass, as follows:

     I_{f} =\frac{1}{2} * m* r^{2} + m_{cl} * r_{cl}^{2} =58.2 kgm2 + (8.7kg)*(1.5m)^{2}  \\  = 58.2 kgm + 19.6 kgm2 = 77.8 kgm2  (4)

  • Replacing I₀, If and ω₀ in (2), we can solve for ωf, as follows:

        \omega_{f}  = \frac{I_{o} *\omega_{o} }{I_{f}} = \frac{58.2kgm2*7.3rad/s}{77.8kgm2}  = 5.5 rad/s (5)

4 0
3 years ago
All of the waves in the electromagnetic spectrum are _______ waves.
neonofarm [45]
 I think the answer you are looking for A compression wave.
4 0
3 years ago
Read 2 more answers
An underwater diver sees the sun at an apparent angle of 45.00 from the vertical. How far is the sun above the horizon? [n in wa
pantera1 [17]

Answer:

19.872 degrees

Explanation:

Mathematically;

Using Snell’s law

n1 sin A = n2 sinB

Where ;

n1 = refractive index in air = 1

n2 is refractive index in water = 1.33

A = ?

B = 45

Substituting the values in the equation;

1 sin A = 1.33 sin45

Sin A = 1.33 sin 45

A = arc sin (1.33 sin 45)

A = 70.12

Thus, the actual direction of the Sun with respect to the horizon = 90-A = 19.872 degrees

6 0
4 years ago
n a local coffee shop, a customer slides her empty nitro cold brew downthe counter for a refill. The barista is distracted, and
Marta_Voda [28]

Answer:

5 m/s

Explanation:

Horizontal distance traveled, x = 2 m

vertical distance traveled, y =  4/5 m

Let the speed of cup as it leaves the counter is v and it takes time t to hit the ground.

Use second equation of motion in vertical direction

y = ut+\frac{1}{2}at^{2}

Here acceleration in vertical direction is 9.8 m/s^2.

So,

\frac{4}{5} = 0+\frac{1}{2}\times9.8t^{2}

t = 0.4 second

Now in horizontal direction the acceleration in zero.

Horizontal distance = horizontal velocity x time

x = v t

2 = v (0.4)

v = 5 m/s

Thus, the horizontal velocity of cup as it leaves the counter is 5 m/s.

4 0
3 years ago
A gas at 5.00 atm pressure was stored in a tank during the winter at 5.0 °C. During the summer, the temperature in the storage a
saw5 [17]

Answer:

a) 5.63 atm

Explanation:

We can use combined gas law

<em>The combined gas law</em> combines the three gas laws:

  • Boyle's Law,   (P₁V₁ =P₂V₂)
  • Charles' Law  (V₁/T₁ =V₂/T₂)
  • Gay-Lussac's Law.  (P₁/T₁ =P₂/T₂)

It states that the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant.

P₁V₁/T₁ =P₂V₂/T₂

where P = Pressure, T = Absolute temperature, V = Volume occupied

The volume of the system remains constant,

So, P₁/T₁ =P₂/T₂

a) \frac{5}{278} =\frac{P_2}{313}  \\\\P_2=\frac{5*313}{278}\\ P_2 = 5.63 atm

7 0
4 years ago
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