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WARRIOR [948]
3 years ago
12

2x + 5y = 3 Plz helpppp

Mathematics
2 answers:
Marta_Voda [28]3 years ago
7 0

Answer: y=\frac{3}{5}-\frac{2}{5}x

Step-by-step explanation:

Move the variables to the right:

2x+5y=3

5y=3-2x

Divide both sides:

5y=3-2x

y=\frac{3}{5}-\frac{2}{5} x

Solution:

y=\frac{3}{5}-\frac{2}{5} x

soldi70 [24.7K]3 years ago
3 0
Is this what you’re looking for
y=-2/5x+3/5
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A + B = 40 B + C = 50 C + A = 30 Give a whole number value for A, B and C to make the above true. A = _____ B = _____ C = _____
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A motorboat can go 16 miles downstream on a river in 20 minutes. It takes 30 minutes for this boat to go back upstream the same
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Prove that the triangle EDF is isosceles. Give reasons for your answer.
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Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
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