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Vlada [557]
3 years ago
10

Determine tge energy in joules of a photon whose frequency is 3.55x10

Physics
1 answer:
JulijaS [17]3 years ago
6 0
E = hf
E = 6.63×10^-34 × 3.55×10 eV
1 eV = 1.60×10^-19 J
E = 6.63×10^-34 × 3.55×10 × 1.60×10^-19
E = 3.77×10^-51 J

Hope it helped!
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In a game of angry birds you launch a bird with an angle of 53 degrees to horizontal. Unfortunatly, its not a good shot and the
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Answer:

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The horizontal distance covered is 9.81 m.

The total time in the air is 1.63 seconds.

Explanation:

The launch speed, u_0= 10 m/s.

Angle of launch with the horizontal, \theta = 53 ^{\circ}

So, the vertical component of the initial velocity,

u_0\sin\theta=10 \sin 53 ^{\circ}\cdots(i).

The horizontal component of the initial velocity,

u_0\cos\theta=10 \cos 53 ^{\circ}

Let, t be the time of flight, to the horizontal distance covered

D=10 \cos (53 ^{\circ})t\cdots(ii).

Not, applying the equation of motion in the vertical direction.

s= ut +\frac 1 2 at^2

Where s is the displacement in time t, u is the initial velocity and a is the acceleration.

In this case, u =10 \sin 53 ^{\circ} (from equation (i), s=0 (as the final height is same as the launch height) and a = -9.81 m/s^2 (negative sign is due to the downward direction).

\Rightarrow 0 = 10 (\sin 53 ^{\circ})t-\frac 1 2 (9.81)t^2

\Rightarrow t= \frac {2\times 10 (\sin 53 ^{\circ})}{9.81}=1.63 seconds.

So, the total time in the air is 1.63 seconds.

From equation (i),

Total horizontal distance covered is

D=10 \cos (53 ^{\circ})\times 1.63 = 9.81 m.

Now, for the maximum height, H, applying the equation of motion as

v^2=u^2+2as

Here, v is the final velocity and v=0 (at the maximum height), and h=H.

So, 0^2=(10 \sin 53 ^{\circ})^2-2(9.81)H

\Rightarrow H = \frac {(10 \sin 53 ^{\circ})^2}{2\times 9.81}

\Rightarrow H = 3.25 m.

Hence, the maximum height covered is 3.25 m.

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I was an American inventor and businessman who is best known for inventing the electric light bulb. Who am I?
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3 years ago
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An airplane flies 1350km in 2 1/4 hours. What is its average speed in kilometers per hour?
Brut [27]
600km since it would be 1350 divided by 2.25
8 0
3 years ago
You see a lightning bolt flash in the distant sky. You hear the corresponding thunder 6.8 seconds later. If the temperature is 2
Anna35 [415]

Answer:

Distance = 2.4\ km

Explanation:

Given

Time (t) = 6.8s

Temperature = 28C

Required

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At about 28C, the speed of sound is 346m/s

So, we have the following:

Speed = 346m/s

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Distance is calculated as thus:

Distance = Speed * Time

Distance = 346m/s * 6.8s

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Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis. The magnitude of q1 is 3 times the magnitu
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d = distance between the two point charges = 60 cm = 0.60 m

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q_{1} = 3 q_{2}

E_{1} = Electric field by charge q_{1} at point "a"

E_{2} = Electric field by charge q_{2} at point "a"


Electric field by charge q_{1} at point "a" is given as

E_{1} = kq_{1} /r²

Electric field by charge q_{2} at point "a" is given as

E_{2} = kq_{2} /(d-r)²

For the electric field to be zero at point "a"

E_{2} = E_{1}

kq_{2} /(d-r)² = kq_{1} /r²

q_{2} /(d-r)² = 3q_{2} /r²

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r = 0.38 m

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