X =0.75,2 i hope this helps you
Answer:
E =230.4 MJ
Explanation:
As 1 mole of electron = 6X 10^23 particles.
charge of an electron is 1.6 X 10 ^-19 C
Finding Charge:
(6X10^23 ) (2.7)(1.6X10^-19 C)
i.e. 192 K C
now to find the energy released from electrons
V=E/q
E=V X q
i.e E = 120 V X 192 K C
E =230.4 MJ
Answer: The magnitude of the force exerted on the roof is 490522.5 N.
Explanation:
The given data is as follows.
Below the roof,
= 0 m/s
At top of the roof,
= 39 m/s
We assume that
is the pressure at lower surface of the roof and
be the pressure at upper surface of the roof.
Now, according to Bernoulli's theorem,


= ![0.5 \times 1.29 \times [(39)^{2} - (0)^{2}]](https://tex.z-dn.net/?f=0.5%20%5Ctimes%201.29%20%5Ctimes%20%5B%2839%29%5E%7B2%7D%20-%20%280%29%5E%7B2%7D%5D)
= 
= 981.045 Pa
Formula for net upward force of air exerted on the roof is as follows.
F = 
= 
= 490522.5 N
Therefore, we can conclude that the magnitude of the force exerted on the roof is 490522.5 N.
Answer:
45 m/s
Explanation:
162 / 3.6 = 45 m/s
Divide by 3.6 to convert km/h to m/s.
Answer:
by using a magnetic field