Answer:
2.866 x 10^8 J
Explanation:
Thermal conductivity, K = 0.040 W/m^2 k
Area of the wall, A = 470 m^2
Thickness, d = 17 cm = 0.17 m
difference in temperature, ΔT = 30° C
The rate of heat flow is H.
Time, t = 1 day = 1 x 24 x 60 x 60 second = 86400 second
By use of formula of heat flow


H = 2.866 x 10^8 J
A. You are exposed to nuclear radiation every day.
We have that the maximum height reached by the basketball from its release point is

From the question we are told
- A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance.
- What is the maximum height reached by the basketball from its release point?
Generally the Newtons equation for Motion is mathematically given as


Therefore
The maximum height reached by the basketball from its release point is

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Answer:
A because it is the most affective way to do it
Explanation: