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goldfiish [28.3K]
3 years ago
15

A guitar string is fixed at both ends. If you tighten it to increase its tension, the frequencies of its normal modes will incre

ase but its wavelengths will not be affected.
A. True
B. False
Physics
1 answer:
faltersainse [42]3 years ago
4 0

Answer:True

Explanation:

We know that frequency in a tight string is given by

\nu =\sqrt{\frac{T}{\mu }}

where \nu =Frequency\ of\ sound\ waves

T=Tension

\mu =mass\ per\ unit\ length

and velocity is given by

v=\nu \lambda

As \nu increases v also increase but wavelength (\lambda) remain same because ends of string are fixed.                    

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The horizontal beam in Fig. E11.14 weighs 190 N, and its center of gravity is at its center. Find (a) the tension in the cable a
grandymaker [24]

Answer:

(a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

Explanation:

Given that,

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According to figure,

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F_{x}=T\cos\theta

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F_{x}=658.33\times\dfrac{4}{5}

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(c). We need to calculate the vertical components of the force exerted on the beam at the wall

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Put the value into the formula

F_{y}=190+300-658.33\times\dfrac{3}{5}

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(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

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Information that is given:
a = -5.4m/s^2
v0 = 25 m/s
---------------------
S = ?
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0 = v0^2 - 2aS
v0^2 = 2aS
S = v0^2/2a
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