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goldfiish [28.3K]
4 years ago
15

A guitar string is fixed at both ends. If you tighten it to increase its tension, the frequencies of its normal modes will incre

ase but its wavelengths will not be affected.
A. True
B. False
Physics
1 answer:
faltersainse [42]4 years ago
4 0

Answer:True

Explanation:

We know that frequency in a tight string is given by

\nu =\sqrt{\frac{T}{\mu }}

where \nu =Frequency\ of\ sound\ waves

T=Tension

\mu =mass\ per\ unit\ length

and velocity is given by

v=\nu \lambda

As \nu increases v also increase but wavelength (\lambda) remain same because ends of string are fixed.                    

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A car traveling at 60 mph has how much more energy than a car going at 15 mph?
VikaD [51]

Answer:

No, if a car is going faster. The RPM is obviously higher. If that is higher, you can burn through gas and energy much faster. A car going at 15mph would be cruising and wouldn't have to worry too much about burning our your vehicle.

Explanation:

7 0
3 years ago
A projectile is fired at v 0 = 381.0 m/s at an angle of θ = 73.5 ∘ , with respect to the horizontal. Assume that air friction wi
Ipatiy [6.2K]

Answer:

Explanation:

velocity of projection, vo = 381 m/s

angle of projection, θ = 73.5°

The formula for the range is

R=\frac{u^{2}Sin2\theta }{g}

R=\frac{381^{2}Sin147 }{9.8}

R = 8067.4 m

Range in shorten by 34.1 %

So, the new range is

R' = 8067.4 - 34.1 x 8067.4/100

R' = 5316.4 m

5 0
3 years ago
In one experiment, the students allow the block to oscillate after stretching the spring a distance A. If the potential energy s
atroni [7]

Answer:

    K = m g (A - A2)

Explanation:

In a block spring system the total energy is the sum of the potential energy plus the kinetic energy, for maximum elongation all the energy is potential

         Em = U₀ = m g A

For when the system is at an ele

Elongation A2 less than A, energy has two parts

        Em = K + U₂

       K = Em –U₂

We substitute

     K = m g A - m gA2

    K = m g (A - A2)

3 0
4 years ago
Read 2 more answers
Which layer of the earth includes the ozone layer
Rus_ich [418]
Troposphere is the answer
7 0
3 years ago
An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid
Katena32 [7]

Answer:

666000000000 J

391764.71 N

Explanation:

u = Initial velocity

v = Final velocity

s = Displacement

Change in energy

\Delta KE=\frac{1}{2}m(v^2-u^2)\\\Rightarrow \Delta KE=\frac{1}{2}3.7\times 10^4(4500^2-7500^2)\\\Rightarrow \Delta KE=-666000000000\ J

Work done be the force is 666000000000 J

W=F\times s\\\Rightarrow F=\frac{W}{s}\\\Rightarrow F=\frac{-666000000000}{1.7\times 10^6}\\\Rightarrow F=-391764.71\ N

The magnitude of force is 391764.71 N

3 0
3 years ago
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