Answer:
I need the answer too someone plzzz answer this!!!
Explanation:
Answer:
ΔE = -2661 KJ/mole
ΔH = -2658 KJ/mole
Explanation:
ΔH = q - PΔV
ΔE = q + w
<u>First, to find ΔE:</u>
The reaction PRODUCES 2658 kJ of h (q), and does 3 kJ of work (w).
2658 kJ(q) + 3 kJ(w) = 2661 kJ, BUT the reaction <u><em>PRODUCES</em></u> heat, which means ΔE is negative.
ΔE = -2661 KJ/mole
<u>Second, to find ΔH:</u>
ΔH = q - PΔV
ΔH = 2658 kJ(q) - PΔV
Now, the question states that butane burns at a constant pressure; that just translates to the pressure of the reaction is equal to 0.
ΔH = 2658 KJ(q) - (0)ΔV
ΔH = 2658 KJ - 0
ΔH = 2658 kJ, BUT, like before, the reaction PRODUCES heat, which also mean ΔH is negative.
ΔH = -2658 KJ/mole
I hope this helped! Have a nice week.
Put the cation (a positive ion, the metal in this case,) without changing anything, then the nonmetal, or anion. For the nonmetal, change the ending to -ide. For example, if you have potassium and chlorine, you would have potassium chloride. Hope this helps!
Answer: Explanation:
Temperatura. La solubilidad de un soluto en un determinado solvente principalmente depende de la temperatura. Para muchos sólidos disueltos en el agua líquida, la solubilidad aumenta con la temperatura hasta 100 °C, aunque existen casos que presentan un comportamiento inverso.
