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liraira [26]
3 years ago
13

Rectangle A has length 12 and width 8. Rectangle B has length 15 and width 10. Rectangle C has length 30 and width 15.

Mathematics
1 answer:
Sidana [21]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

rectangle a has a 2 to 3 ratio in length and width same with rectangle b

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how many ways an employer send 3 employees to a job fair if she has 11 employees A)165 B)990 C)40,320 D)6,652,800
KIM [24]
To find the number of employees we use combination formula.
n!/(n-r)! r!
Put values
11!/(11-3)! 3!
Simplify
11!/8!3! = 165

Answer: Option A 165
3 0
3 years ago
Sales of a new line of athletic footwear are crucial to the success of a newly formed company, Fleet Shoes. Fleet wishes to esti
Murrr4er [49]

Answer:

The number of weeks required = 216 weeks

Step-by-step explanation:

Given that:

Margin of Error E = 200

Confidence interval = 95% = 0.95

Level of SIgnificance  = 1 - C.I

= 1 - 0.95

= 0.05

Standard deviation = 1500

The Critical value for Z :

Z_{\alpha/2} =Z_{0.05/2}  \\ \\  = Z_{0.025} =  1.96

The number of weeks( i.e the sample size (n) ) required is :

n = (\dfrac{Z_{\alpha/2} \times \sigma}{E})^2

n = (\dfrac{1.96 \times 1500}{200})^2

n = (14.7)^2

n = 216.09

n ≅ 216 weeks

8 0
3 years ago
How do you turn 3/7 to a decimal?
Thepotemich [5.8K]
Divide them on a calculator
8 0
3 years ago
Read 2 more answers
In the interval 0º < x < 360°, find the values of x for which tan x= -0.6745
SSSSS [86.1K]
Tan(θ) = 3 tan(θ), 0° ≤ θ ≤ 360°

Solve for θ to the nearest degree.

tan(θ) = 3 tan(θ)

Subtract tan(θ) from both sides:

0 = 2 tan(θ)

Divide by 2 both sides:

tan(θ) = 0

If (x,y) is a point on the terminal ray of θ,

then tan(θ) = y/x = 0, and y = 0.

y = 0 ==> θ = 0°, 180°, or 360° in the interval 0° ≤ θ ≤ 360°.
7 0
3 years ago
Complete the table of values from left to right for the quadratic function
Lapatulllka [165]

Answer:

The values of y are -33 , -15 , -5 , -5 ⇒ answer C

Step-by-step explanation:

* We will use the substitution method to solve the problem

- The quadratic equation is y = -x² + x - 3

- The values of x are -5 , -3 , -1 , 2

- We will substitute the values of x in the equation to find the

  values of y

# At x = -5

∵ y = -x² + x - 3

∵ x = -5

∴ y = -(-5)² + (-5) - 3 = - 25 - 5 - 3 = -33

∴ y = -33

# At x = -3

∵ y = -x² + x - 3

∵ x = -3

∴ y = -(-3)² + (-3) - 3 = - 9 - 3 - 3 = -15

∴ y = -15

# At x = -1

∵ y = -x² + x - 3

∵ x = -1

∴ y = -(-1)² + (-1) - 3 = - 1 - 1 - 3 = -5

∴ y = -5

# At x = 2

∵ y = -x² + x - 3

∵ x = 2

∴ y = -(2)² + (2) - 3 = - 4 + 2 - 3 = -5

∴ y = -5

* The values of y are -33 , -15 , -5 , -5 ⇒ from left to right

8 0
4 years ago
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