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3 years ago

Predict which of the following transition metal ions has a color Cr3+, Cd2+, Hg2+, V2+

Chemistry

2 answers:

ANEK [815]3 years ago

8 0

Answer:Cr3+ and V2+

Explanation:

Cd and Hg belong to group 12 which is sometimes referred to as post transition elements. They possess a filled d subshell (d10). Remember that the colour of transition elements is attributed to the presence of partially filled d orbitals leading to transition between the three degenerate lower energy t2g orbitals and two higher energy degenerate eg orbitals. If the element has a d10 configuration, such transition is impossible, hence its ions will be colourless.

Delicious77 [7]3 years ago

4 0

Answer:

Cr3+ is green and V2+ is purple. Cr3+ and V2+ are both d3 so there can be a lot of movement between energy levels to produce colored light. Cd2+ and Hg2+ are both d10 (full d orbital, much less electron movement).

Explanation:

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Which of the following is the correct measurement for the volume of liquid shown below?

Svetach [21]

The correct answer is A. The correct measurement for the volume of the liquid shown is 8.5 mL. If the volume of water to be read in a graduated cylinder, it is important to read it in the lower meniscus. This will be the correct reading. Due to surface tension, water attach to the walls of the glass forming a concave at the top surface.

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3 years ago

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Juliette [100K]

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3 years ago

The decomposition of dinitrogen pentaoxide has an activation energy of 102 kJ/mol and ΔH°rxn = + 55 kJ/mol. What is the activati

ahrayia [7]

<u>Answer:</u> The activation energy of the reverse reaction is 47 kJ/mol

<u>Explanation:</u>

The chemical equation for the decomposition of dinitrogen pentaoxide follows:

$N_2O_5\rightleftharpoons 2NO_2+\frac{1}{2}O_2$

We are given:

Activation energy of the above reaction (forward reaction) = 102 kJ/mol

Enthalpy of the reaction = +55 kJ/mol

As, the enthalpy of the reaction is positive, the reaction is said to be endothermic in nature.

To calculate the activation energy for the reverse reaction, we use the equation:

$E_a_{\text{(forward)}}=E_a_{\text{(backward)}}+|\Delta H|$

where,

$E_a_{\text{(forward)}}$ = Activation energy of the forward reaction = 102 kJ/mol

$E_a_{\text{(backward)}}$ = Activation energy of the backward reaction = ?

$\Delta H$ = Enthalpy of the reaction = +55 kJ/mol

Putting values in above equation, we get:

$102=E_a_{\text{(backward)}}+55\\\\E_a_{\text{(backward)}}=(102-55)=+47kJ/mol$

Hence, the activation energy of the reverse reaction is 47 kJ/mol

3 0

3 years ago

2.1 g of a hydrocarbon fuel is burned in a calorimeter that contains 280 grams of water initially at 25.00◦C. After the combusti

olga2289 [7]

Answer:

$\large \boxed{\text{933 J}}$

Explanation:

There are three heat transfers involved.

heat from combustion of propane + heat gained by water + heat gained by calorimeter = 0

q₁ + q₂ + q₃ = 0

m₁ΔH + m₂C₂ΔT + C_calΔT = 0

Data:

m₁ = 2.1 g

m₂ = 280 g

Ti = 25.00 °C

T_f = 26.55 °C

Ccal = 92.3 J·°C⁻¹

Calculations:

Let's calculate the heats separately.

1. q₁

q₁ = 2.1 g × ΔH = 2.1ΔH g

2. q₂

ΔT = T_f - Ti = 26.55 °C - 25.00 °C = 1.55 °C

q₂ = 280 g × 4.184 J·°C⁻¹ × 1.55 °C = 1816 J

3. q₃

q₃ = 92.3 J·°C⁻¹ × 1.55 °C = 143.1 J

4. ΔH

$\begin{array}{rcl}\text{2.1$\Delta$H g +1816 J +143.1 J} & = & 0\\\text{2.1$\Delta$H g +1959 J} & = & 0\\\text{2.1$\Delta$H g}& = & \text{-1959 J}\\\Delta H & = & \dfrac{\text{-1959 J}}{\text{2.1 g}}\\\\& = & \textbf{-933 J/g}\\\end{array}\\\text{The combustion releases $\large \boxed{\textbf{933 J}}$ per gram of fuel burned.}$

7 0

3 years ago

Write a balanced equation showing how this nucleus decays to form an α particle: thorium−230.

Ostrovityanka [42]

When an atomic nucleus emits an alpha particle it decay into an atom with atomic number 2 less and mass number 4 less. Thus Thorium 230 decay as follows.

230 90Th -------> 226 88Th + 4 2 He

thorium is in the atomic number 90 thus it during alpha decay it reduces to atomic number 88 while its 230 mass number reduces to 226

6 0

3 years ago