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Virty [35]
2 years ago
13

What is the difference between the Lewis model and the valence-shell electron pair repulsion (VSEPR) model?

Chemistry
1 answer:
grandymaker [24]2 years ago
8 0

Answer: only the VSEPR mode shows the geometric shape of a formula.

You might be interested in
When does an object move<br><br>​
natulia [17]

Answer:

When a force pushes or pulls the object, the object will move in the direction of the force. The bigger the force, and the lighter the object, the greater the acceleration. It can also make something slow down, speed up or change direction.

Wish I Could HELP You!

5 0
2 years ago
Which of the following is/are considered alcohols?
Paladinen [302]

Answer: THE ANSWER IS D

Explanation:

an alcohol is a hydrocarbon chain with an hydroxyl group (OH)

A, B, AND C ARE ALL ALCOHOLS, SO THE ANSWER IS D

6 0
2 years ago
1. When the temperature of a rigid hollow sphere containing 685 L of helium gas is
mote1985 [20]
<h3>Answer:</h3>

250.756 moles He

<h3>Explanation:</h3>

From the question we are given;

Volume, L = 685 L

Temperature, T = 621 K

Pressure, P = 189 × 10 kPa

We are required to calculate the number of moles of the gas,

Using the Ideal gas equation,

PV = nRT, where P is the pressure, V is the volume, T is the temperature, n is the number of moles, and R is the ideal gas constant.

We can replace the known variables and constant in the equation to get the unknown variable, n.

Using ideal gas constant as 8.3145 L.kPa/K/mol

n=\frac{PV}{RT}

n=\frac{(1890)(685)}{(8.3145)(621)}

n = 250.7557 moles

   n = 250.756 moles

The moles of helium contained in the sphere is 250.756 moles

6 0
2 years ago
The rate of disappearance of HBr in the gas phase reaction2HBr(g) → H2(g) + Br2(g)is 0.301 M s-1 at 150°C. The rate of appearanc
jok3333 [9.3K]

Answer: 0.151

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2HBr(g)\rightarrow H_2(g)+Br_2(g

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=-\frac{1d[HBr]}{2dt}=+\frac{1d[H_2]}{2dt}=+\frac{1d[Br_2]}{dt}

Given: -\frac{d[HBr]}{dt}]=0.301

Putting in the values we get:

\frac{0.301}{2}=+\frac{1d[Br_2]}{dt}

+\frac{1d[Br_2]}{dt}=0.151

Thus the rate of appearance of Br_2 is 0.151

8 0
3 years ago
WILL GIVE BRAINLIEST!<br> Calculate the bond for CO2
yawa3891 [41]

Answer:

Bonding Order = number of bonding electrons – number of antibonding electrons/2.

So for CO2, there is a total of 16 electrons, 8 of which are antibonding electrons.

So 16 – 8 = 8; divided by 2 = 4. So, 4 is the bonding order of CO2. The molecular structure of CO2 looks like this:

..~-~~..

O=C=O

..~-~~..

5 0
3 years ago
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