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ohaa [14]
3 years ago
10

3.0 L of oxygen gas is heated from 100k to 250k. What is the new volume after the temperature has been increased???

Chemistry
1 answer:
alexandr402 [8]3 years ago
7 0

Answer:

7.5 L

Explanation:

Using Charles' law, which is V1/T1=V2/T2, we can plug in these numbers to find the answer.  The law states that volume is directly proportional to temperature. 3.0L/100K = x L / 250 K. Solve for x to get 7.5 L. Hope this helps.

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In chemistry what is Faraday's law​
Eduardwww [97]

Answer:

<u><em>Faraday’s – First Law of Electrolysis</em></u>

<u><em>It is one of the primary laws of electrolysis. It states, during electrolysis, the amount of chemical reaction which occurs at any electrode under the influence of electrical energy is proportional to the quantity of electricity passed through the electrolyte.</em></u>

<u><em></em></u>

<u><em>Faraday’s – Second Law of Electrolysis</em></u>

<u><em>Faraday’s second law of electrolysis states that if the same amount of electricity is passed through different electrolytes, the masses of ions deposited at the electrodes are directly proportional to their chemical equivalents.</em></u>

<u><em></em></u>

<u><em>From these laws of electrolysis, we can deduce that the amount of electricity needed for oxidation-reduction depends on the stoichiometry of the electrode reaction.</em></u>

<u><em>The product of an electrolytic reaction depends on the nature of the material being electrolysed and the type of electrodes used. In the case of an inert electrode such as platinum or gold, the electrode does not participate in the chemical reaction and acts only as a source or sink for electrons. While, in the case of a reactive electrode, the electrode participates in the reaction.</em></u>

<u><em></em></u>

<u><em>Hence, different products are obtained for electrolysis in the case of reactive and inert electrodes. Oxidizing and reducing species present in the electrolytic cell and their standard electrode potential too, affect the products of electrolysis.</em></u>

<u><em></em></u>

<u><em>FAQs</em></u>

<u><em>1. What’s a Faraday?</em></u>

<u><em>Ans: The Faraday is an electric charge volume unit without measurements, equal to approximately 6.02 x 10 23 electric charge carriers.</em></u>

<u><em></em></u>

<u><em>2. Why is Faraday’s law important?</em></u>

<u><em>A shifting magnetic flux creates an electric field, according to Faraday’s law. Faraday’s law is particularly important since it addresses the connection of the E-field and the B-field and understands that this connection necessitates flux fluctuation over time.</em></u>

<u><em></em></u>

<u><em>3. How does electrolysis remove rust?</em></u>

<u><em>Ans: Electrolysis is a method of removing iron oxide by passing a small electrical charge through the rusty metal from a battery or battery charger to induce ion exchange while the device is submerged in an electrolyte solution.</em></u>

<u><em></em></u>

<u><em>4. What happens to water during electrolysis?</em></u>

<u><em>Ans: Water’s Electrolysis. By passing an electrical current through it, water can be decomposed. When this happens, an oxidation-reduction reaction is caused by the electrons from the electric current.</em></u>

<u><em></em></u>

<u><em>5. What is the negative electrode called in electrolysis?</em></u>

<u><em>Ans: Through electrolysis, the negatively charged electrode is called the cathode. The positively charged electrode is called the anode in electrolysis. Negatively charged ions are moving towards the anode.</em></u>

<u><em></em></u>

<em>Hope it helps!</em>

5 0
2 years ago
Read 2 more answers
Combustion analysis of 0.300 g of an unknown compound containing carbon, hydrogen, and oxygen produced 0.5213 g of co2 and 0.283
Lyrx [107]
First, we have to get how many grams of C & H & O in the compound:
- the mass of C on CO2 = mass of CO2*molar mass of C /molar mass of CO2
                                        = 0.5213 * 12 / 44 = 0.142 g
- the mass of H atom on H2O = mass of H2O*molar mass of H / molar mass of H2O
                                                 =0.2835 * 2 / 18 = 0.0315 g
- the mass of O = the total mass - the mass of C atom - the mass of H atom
                          =  0.3 - 0.142 - 0.0315 = 0.1265 g
Convert the mass to mole by divided by molar mass
C(0.142/12) H(0.0315/2) O(0.1265/16) 
C(0.0118) H(0.01575) O(0.0079) by dividing by the smallest value 0.0079
C1.504 H3.99 O1 by rounding to the nearst fraction
C3/2 H4/1 )1/1 multiply by 2 
∴ the emprical formula C3H8O2
           



6 0
3 years ago
7.<br> How many grams are contained in 3.9 x 1023 sulfur atoms?<br> atoms → moles<br> grams<br> I
Anni [7]

Answer: 20.775 g S

Explanation: 3.9x10^23 atoms = 0.648 mol

Atomic mass S = 32.08

S in grams = 20.775

4 0
3 years ago
A scientist is unsure about the accuracy of her experiment. She has checked her equipment and found it to be in good working ord
polet [3.4K]

Answer:

D

Explanation:

The correct thing to do in this case would be to <u>repeat the experiment.</u>

The scientist would need to repeat the experiment in order to double-check the accuracy. If the accuracy is indeed doubtful, he/she can be able to trace the source of the error by repeating the experiment.

The correct option is D.

8 0
3 years ago
How long would it take for an 88.0 gram sample to decay to only 5.50 grams if it has a half-life of 16.4 seconds?
a_sh-v [17]

Answer: 65.23

Explanation:

3 0
3 years ago
Read 2 more answers
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