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dimulka [17.4K]
3 years ago
5

The mutchkin and the noggin a mutchkin is a scottish unit of liquid measure equal to 0.42 l. How many mutchkins are required to

fill a container that measures one foot on a side?
Chemistry
2 answers:
I am Lyosha [343]3 years ago
8 0

Answer:

67.41Mutchkin

Explanation:

Hello,

In this case, the equivalence is:

1Mutchkin=0.42L

Thus, the volume of the container is based on the given one foot on a side as:

V=1ft^3

In addition, the equivalence between cubic feet and liters is:

1ft^3=28.317L

Thus, the mutchkins turns out:

1ft^3*\frac{28.317L}{1ft^3} *\frac{1Mutchkin}{0.42L} =67.41Mutchkin

Best regards.

Rasek [7]3 years ago
6 0

Given that 1 mutchkin (a scottish unit) = 0.42 L

Now the volume of container (assuming it to be cubical, as only one side is given) = a^3 = 1^3 = 1ft^3

Now 1 foot = 3.048 dm [1 decimeter= 0.1 m]

Hence 1 ft X 1ft X 1ft = 3.048 X 3.048 X 3.048 dm^3 = 28.32 dm^3

We know that 1L =  1 dm^3

therefore volume of container in Litres = 28.32 L

now as given that 0.42 L = 1 mutchkin

therefore 1 L = 1 / 0.42 mutchkin

28.32 L = 28.32 / 0.42 mutchkin = 67.43 mutchkins [This much mutchkin is required to fill the container]


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From given information, 10.0 mL of original acid solution were taken in a 100 mL flask and water was added up to the mark. It means the 10 fold dilution is done. 10 fold dilution means the molarity becomes one tenth of it's original value. Let's do the calculations in reverse way as we have calculated the molarity of the final solution.

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Y(10.0mL) = 0.170M(100mL)

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Hence, the actual molarity of sulfuric acid solution is 17.0M.

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