First step is to calculate the mole of each element
that is;
carbon 97.6/12=8.13moles
hydrogen= 4.9/1=4.9 moles
oxygen 52/16=3.25 moles
nitrogen=45.5/14=3.25 moles
step two is to calculate the mole ratio by dividing with the smallest number of moles
that is divide each mole with 3.25moles
carbon=8.13/3.25 =5/2
hydrogen=4.9/3.25= 3/2
oxygen=3.25/3.25=1
nitrogen=3.25/3.25=1
step 3; multiply all the mole ratio by 2 to remove the fraction
carbon=5/2 x2 =5
hydrogen=3/2 x2=3
oxygen=1 x2=2
nitrogen =1x2=2
therefore the empirical formula is C5H3O2N2(answer c)
Answer:
second order
Explanation:
units of reaction and their order.
Zero order --> M^1 s^-1 = M/s
First order --> M^0 s^-1 = 1/s
Second order --> M^-1 s^-1 = L/mol s
In the question rate constant k = 4.65 L mol-1s-1. = 4.65 L/mol s
Hence, the reaction is a second order reaction
From ideal gas equation PV = nRT, V/T = nR/P ==> V/T = constant. Therefore V1/T1 = V2/T2 ==> 7.8/698 = V2/308. V = 3.44L {TEMPERATURE IN KELVIN = 273 + 425 AND 35 = 698 AND 308}
Answer:
186 Liters at STP conditions
Explanation:
1 mole of any gas at STP conditions occupies 22.4 Liters.
Therefore, 8.32 moles O₂(g) = 8.32 moles x 22.4Liters/mole = 186 Liters (3 sig.figs.)
