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attashe74 [19]
3 years ago
6

Help plz:)))I’ll mark u Brainliest

Chemistry
1 answer:
Triss [41]3 years ago
6 0

Answer:

Explanation:

We want the energy required for the transition:

CO  2 ( s ) + Δ → C O 2 ( g )

Explanation:

We assume that the temperature of the gas and the solid are EQUAL.

And thus we simply have to work out the product:

2 × 10^ 3 ⋅ g × 196.3 ⋅ J ⋅ g − 1  to get an answer in  Joules  as required.

What would be the energy change for the reverse transition:

C O 2 ( g ) + → C O 2 ( s ) ?

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Nataliya [291]

Explanation:

The given data is as follows.

        Specific heat of water = 4.18 J/g^{o}C

        Heat of fusion of water = 334 J/g

        Mass of water = 200 g

On bringing water at 0^{o}C, heat released will be as follows.

            q_{1} = m \times C \times \Delta T

                    = 200 g \times 4.18 J/g^{o}C \times (0 - 15)^{o}C

                    = -12540 J

or,                = -12.540 kJ           (as 1 kJ = 1000 J)

Now, calculate the heat releasedwhen water freezes at 0^{o}C as follows.

                q_{2} = mass \times \text{-heat of fusion}

                         = 200 g \times -334 J/g

                         = -66800 J

or,                      = -66.80 kJ

Therefore, total heat released in freezing water will be as follows.

                     q_{total} = q_{1} + q_{2}

                              = (-12.540 - 66.80) kJ

                              = -79.34 kJ

Hence,

       amount of heat released in freezing water = heat used to vaporize CCl_{2}F_{2}

Now, heat of vaporization of CCl_{2}F_{2} = 289 J/g

Total heat released in freezing water = -79.34 kJ

Heat consumed to vaporize CCl_{2}F_{2} = 79.34 kJ = -79340 J

Therefore, calculate the mass of CCl_{2}F_{2} vaporized as follows.

              Mass of CCl_{2}F_{2} vaporized = \frac{\text{heat consumed}}{\text{heat of vaporization}}

                              = \frac{79340 J}{289 J/g}

                              = 274.53 g

Thus, we can conclude that 274.53 g mass of this substance must evaporate to freeze 200 g of water initially at 15^{o}C.

5 0
4 years ago
Hat is the molar mass of a substance?
Morgarella [4.7K]
The molar mass is what would you find on the periodic table and it is used in the mole conversions within chemistry. So the answer would have to be A: the mass in grams of one mole of a substance. 
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The physical state of CaBr2 at room temperature? Predict the two other properties of CaBr2 Deduce the charge of ion Ca in the co
Fofino [41]

Answer:

CaBr2 is a colorless solid and the charge on Calcium is +2

Explanation:

CaBr2 is a colorless solid at room temperature.

Other properties include -

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c) It is deliquescent

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Which of the following would help you identify a titration curve that involved a strong acid titrated by a weak base?
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Answer:

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Given the titration involves a strong acid and a weak base

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If a chemical indicator is used—methyl orange would be a good choice in this case—it changes from its basic to its acidic colour.

In strong acid-weak base titrations, the pH at the equivalence point is not 7 but below it. This is due to the production of a conjugate acid during the titration; it will react with water to produce hydronium ions.

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All but one product of the light dependent reaction of photosynthesis is utilized in the light independent reaction. That is
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