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3 years ago

Help plz:)))I’ll mark u Brainliest

Chemistry

1 answer:

Triss [41]3 years ago

6 0

Answer:

Explanation:

We want the energy required for the transition:

CO 2 ( s ) + Δ → C O 2 ( g )

Explanation:

We assume that the temperature of the gas and the solid are EQUAL.

And thus we simply have to work out the product:

2 × 10^ 3 ⋅ g × 196.3 ⋅ J ⋅ g − 1 to get an answer in Joules as required.

What would be the energy change for the reverse transition:

C O 2 ( g ) + → C O 2 ( s ) ?

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Calculate the volume in liters of a 0.00231M copper(II) fluoride solution that contains 175.g of copper(II) fluoride CuF2. Be su

Free_Kalibri [48]

Answer:

Volume = 746 L

Explanation:

Given that:- Mass of copper(II) fluoride = 175 g

Molar mass of copper(II) fluoride = 101.543 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{175\ g}{101.543\ g/mol}$

$Moles_{copper(II)\ fluoride}= 1.7234\ mol$

Also,

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

So,,

$Volume =\frac{Moles\ of\ solute}{Molarity}$

Given, Molarity = 0.00231 M

So,

$Volume =\frac{1.7234}{0.00231}\ L$

Volume = 746 L

7 0

3 years ago

What is the molar mass of sulfur (S)?

Lesechka [4]

Answer:

A. 32.06 g/mol

Explanation:

The molar mass units are always g/mol

8 0

3 years ago

Read 2 more answers

What would be the molarity of a solution in which 0.56 mole of NaCl is dissolved in enough water to make 2.7 L of solution?

yan [13]

Answer:

Molarity = 0.21 M

Explanation:

Moles solute (mol) = Volume solution (L) x Molarity solution (M)

0.56 mol NaCl = 2.7 L x M

M = 0.2074074074

5 0

2 years ago

Use the balanced equation from number four above to determine the limiting reactant if we had a mixture of 5.0 moles of Fe and 4

Tom [10]

Answer:

2Fe + 3O₂ → 2Fe₂O₃

Limiting reactant: O₂

2Fe + O₂ → 2FeO

Limiting reactant: Fe

Explanation:

2Fe + 3O₂ → 2Fe₂O₃

2Fe + O₂ → 2FeO

These are the possible reactions:

In first case, 2 moles of Fe need 3 mol of oyxgen to react

If I have 5 moles of Fe, I will need (5 .3)/2 = 7.5 moles of O₂

Then, the oxygen is my limiting ( I only have 4 moles)

3 moles of O₂ need 2 moles of Fe

If I have 4 moles of O₂, I will need (4 .2)/3 = 2.66 moles (I have 5)

Fe, is the reactant in excess.

For second case, 2 moles of Fe need 1 mol of O₂, to react.

If I have 5 moles of Fe, I will need ( 5 .1) / 2 =2.5 moles of O₂

I have 4 moles of oxygen, so now it is my excess.

1 mol of O₂ need 2 moles of Fe, to react

If I have 4 moles of O₂, I will need the double of amount, 8 moles of Fe.

I have 5 moles, then the Fe is my limtiing reactant.

8 0

3 years ago

7 Be + 2 HCl →BeCl2+ H2

Mashutka [201]

Answer:

The percent yield is 42.52%.

Explanation:

Theoretical yield of beryllium chloride = 12.7 g

Actual yield of the beryllium chloride = 5.4 g

The formula used for the percent yield will be :

$\text{Percent yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100$

Now put all the given values in this formula, we get:

$\%(yield)=\frac{5.4 g}{12.7 g}\times 100=42.52\%$

The percent yield is 42.52%.

3 0

3 years ago