Answer:
2 to the power of one sixth
Step-by-step explanation:
Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:
So you can rewrite the given fraction as
and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:
Since
the answer is
Answer:
Step-by-step explanation:
<u><em>8).</em></u>
<em>(2)</em> × [ - 3 ]
4x + 3y = 1 ........ <em>(3)</em>
- 3x - 3y = - 6 .... <em>(4)</em>
<em>(3)</em> + <em>(4)</em>
x = - 5
- 5 + y = 2 ⇒ y = 7
<em>( - 5 , 7 )</em>
<u><em>9).</em></u>
<em>(1)</em> ÷ [- 3]
3x - y = - 6 ......... <em>(3)</em>
2x + y = - 4 ........ <em>(4)</em>
<em>(3)</em> + <em>(4)</em>
5x = - 10 ⇒ x = - 2
2(- 2) + y = - 4 ⇒ y = 0
<em>(- 2, 0)</em>
<u><em>10).</em></u>
<em>(2)</em> ÷ 10
x - 0.6y = 0 ⇒ x = 0.6y -----> <em>(1)</em>
0.6y - 2y = 14
- 1.4y = 14
y = - 10
x - 2(- 10) = 14 ⇒ x = - 6
<em>(- 6, - 10)</em>
Now is your turn, you can do it!!
