Weight of the body will be more in air water Milk or Mercury

A crate is pulled to the right with a force of 85 N, to the left with a force of 115 N, upward with a force of 565 N, and downwa

balandron [24]

Answer:

330.4 N and $95.2^{\circ}$ counterclocwise to the x direction

Explanation:

Sum of forces in vertical are equal, let movement to right and upwards be positive while left and downwards be negative

Net force in horizontal direction is 85-115=-30 N

Net force in vertical direction is 565-236=329 N

Resultant force= $\sqrt {(-30)^{2}+329^{2}}=330.3649497 N\approx 330.4 N$

Direction= $tan^{-1}\frac {329}{-30}=-84.78986932\approx -84.8^{\circ}$

180-84.8=95.2

Therefore, direction is $95.2^{\circ}$ counterclocwise to the x direction

3 0

4 years ago

Calculate the ionization potential for C+5 ( 5 electrons removed for the C atom) and in addition compute the wavelength of the t

sveta [45]

Answer:

Ionization potential of C⁺⁵ is 489.6 eV.

Wavelength of the transition from n=3 to n=2 is 1.83 x 10⁻⁸ m.

Explanation:

The ionization potential of hydrogen like atoms is given by the relation :

$E = \frac{13.6Z^{2} }{n^{2} } eV$ .....(1)

Here E is ionization potential, Z is atomic number and n is the principal quantum number which represents the state of the atom.

In this problem, the ionization potential of Carbon atom is to determine.

So, substitute 6 for Z and 1 for n in the equation (1).

$E = \frac{13.6\times(6)^{2} }{1^{2} }$

 E = 489.6 eV

The wavelength (λ) of the photon due to the transition of electrons in Hydrogen like atom is given by the relation :

$\frac{1}{\lambda} =RZ^{2}[\frac{1}{n_{1} ^{2}}-\frac{1}{n_{2} ^{2} }]$ ......(2)

R is Rydberg constant, n₁ and n₂ are the transition states of the atom.

Substitute 6 for Z, 2 for n₁, 3 for n₂ and 1.09 x 10⁷ m⁻¹ for R in equation (2).

$\frac{1}{\lambda} =1.09\times10^{7} \times6^{2}[\frac{1}{2 ^{2}}-\frac{1}{3 ^{2} }]$

$\frac{1}{\lambda}$ = 5.45 x 10⁷

λ = 1.83 x 10⁻⁸ m

7 0

4 years ago

This diagram shows how a certain type of precipitation is formed. Water drops are caught in up-drafts and down-drafts, over and

Svet_ta [14]

It would be B. Hail.

5 0

4 years ago

Consider the following statements. A. Heat flows from an object at higher temperature to an object at lower temperature; B. Heat

Monica [59]

Answer:

A. Heat flows from an object at higher temperature to an object at lower temperature

Explanation:

The option A obeys the 2nd law of thermodynamics. The heat will flow from the object at higher temperature to the object at Lower temperature till they reach an equilibrial state.

Heat doesn’t necessarily flow from an object with higher thermal energy to an object with lower thermal energy because an object has a higher thermal energy when it’s mass is more than the other. This makes B wrong.

C is wrong because heat moves from an object with higher temperature to objects with Lower temperature regardless of the state of matter.

8 0

3 years ago

Gayle runs at a speed of 3.85 m/s and dives on a sled, initially at rest on the top of a frictionless snow-covered hill. After s

enot [183]

Answer:

Final velocity at the bottom of hill is 15.56 m/s.

Explanation:

The given problem can be divided into four parts:

1. Use conservation of momentum to determine the speed of the combined mass (Gayle and sled)

From the law of conservation of momentum (perfectly inelastic collision), the combined velocity is given as:

$p_i = p_f$