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3 years ago

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In a fission experiment observed by Hahn and Strassman, uranium-235 was bombarded by neutrons. The products of this ission react

ion included two light nuclei, barium-137
and krypton-84. What was another product of this nuclear reaction?
water
energy
hydrogen-1
helium-4

1 answer:

wlad13 [49]3 years ago

7 0

Answer:

helium-4 (90%) or tritium (7%).

Explanation:

hope it helped u buddy

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If you throw a raw egg against a wall, you'll break it, but if you throw it with the same speed into a sagging sheet it won't br

SashulF [63]

<span>The egg doesn't break when it hits the sheet because the impact time is longer. Momentum means the egg is slowed rather than coming to an abrubt halt. The softer the object that the egg hits, the longer the time it takes to break. A sheet is so soft that the force is never high enough for the egg to break.</span>

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2 years ago

Calculate the propellant mass required to launch a 2000 kg spacecraft from a 180 km circular orbit on a Hohmann transfer traject

Finger [1]

Answer:

t = 12,105.96 sec

Explanation:

Given data:

weight of spacecraft is 2000 kg

circular orbit distance to saturn = 180 km

specific impulse = 300 sec

saturn orbit around the sun R_2 = 1.43 *10^9 km

earth orbit around the sun R_1= 149.6 * 10^ 6 km

time required for the mission is given as t

$t = \frac{2\pi}{\sqrt{\mu_sun}} [\frac{1}{2}(R_1 + R_2)]^{3/2}$

where

$\mu_{sun}$ is gravitational parameter of sun = 1.32712 x 10^20 m^3 s^2. $t = \frac{2\pi}{\sqrt{ 1.32712 x 10^{20}}} [\frac{1}{2}(149.6 * 10^ 6 +1.43 *10^9 )]^{3/2}$

t = 12,105.96 sec

6 0

3 years ago

MA of the first class lever may be equal to, greater than 1.Why

Anika [276]

Answer:

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Explanation:

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4 0

3 years ago

(answer fast and correctly and i will give you brainiest and 5 star's. )

oee [108]

Answer:

Energy cannot be created or destroyed.

Explanation:

its in the name, law of "conservation" of energy. energy can only change forms not be destroyed

7 0

2 years ago

Read 2 more answers

Uphill escape ramps are sometimes provided to the side of steep downhill highways for trucks with overheated brakes. For a simpl

o-na [289]

Answer:

404.4 m

Explanation:

Converting the initial speed from km/h to m/s then

$140\times \frac {1000m}{3600s}=38.88888889 m/s \approx 38.89 m/s$

The acceleration is resolved as shown in the figure hence

deceleration of the truck along the inclined plane will be

$a=-g sin \theta$ where g is acceleration due to gravity

Substituting g with $9.81 m/s^{2}$ then

$a=-9.81 m/s^{2} sin 11^{\circ}=-1.871836245\approx -1.87 m/s^{2}$

Using kinematic equation

$v^{2}=u^{2}+2as$ and making s the subject then

$s=\frac {v^{2}-u^{2}}{2a}$ where v and u are final and initial velocities respectively

Substituting 0 for v, 38.89 m/s for u and $-1.87 m/s^{2}$ then

$s=\frac {0^{2}-38.89^{2}}{2\times -1.87}=404.3936096 m\approx 404.4 m$

3 0

2 years ago