The potential difference between the plates will be 1552 Volts.
<h3>What is a potential difference?</h3>
Voltage, or the difference in electric potential between two points, is defined as the amount of labor per unit of charge needed to move a test charge between the two points.
Given that a 3.7-f capacitor that stores sufficient energy to operate a 75.0-w
The potential difference will be calculated by the formula below:-
Q = I t
Where I = charge / time
Q = V * C
V C = I t
V = I t / C
V = 75 C/s x 60 sec / 2.9 faraday
V = 1552 Volts
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Answer: Weight truck+load = 29.4×
N
Explanation: When an object floats in a fluid, there is an upward force, caused by the liquid, acting on the object that opposes the weight of the immersed object. This force is called <u>Buyoyant</u> <u>Force</u> and is determined by:
B = d*V*g
where
d is density of the fluid;
V is volume of liquid displaced due to the immersed object;
g is acceleration due to gravity;
For the truck, the system is in equilibrium, which means buyoyant force is equal weight. Then:
Volume displaced is
V = 10*8*0.0375
V = 3 
Density of water: 1000kg/

= 1000*3*9.8
= 29.4×
N
The weight of the truck and the load is 29.4×
Newtons
<h2>
Mass of object in Earth is 1.37 kg</h2>
Explanation:
On planet B where the magnitude of the free-fall acceleration is 1.91g , the object weighs 25.74 N.
We have
Weight = Mass x Acceleration due to gravity
On planet B
25.74 = Mass x 1.91 g
25.74 = Mass x 1.91 x 9.81
Mass = 1.37 kg
Mass is constant for an object. It will not change with location.
Mass of object in Earth = Mass of object in Planet B
Mass of object in Earth = 1.37 kg
The kilogram is the Standard International System of Units unit of mass. It is defined as the mass of a particular international prototype made of platinum-iridium and kept at the International Bureau of Weights and Measures.
Answer:
The resultant strain in the aluminum specimen is 
Explanation:
Given that,
Dimension of specimen of aluminium, 9.5 mm × 12.9 mm
Area of cross section of aluminium specimen,

Tension acting on object, T = 35000 N
The elastic modulus for aluminum is,
The stress acting on material is proportional to the strain. Its formula is given by :

is the stress

Thus, The resultant strain in the aluminum specimen is 