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svet-max [94.6K]
3 years ago
9

How many watt hours will 3-155amp hour 12 volt batteries wired in a parallel configuration produce?

Physics
1 answer:
Ede4ka [16]3 years ago
4 0

Answer:

B 5580 W•hr

Explanation:

A Watt is a Volt times an Amp

3(12 V(155 A•hr)) = 5580 W•hr

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A runner starts from rest and accelerates uniformly to a speed of 8.0 meters per second in 4.0 seconds. the magnitude of the acc
Paha777 [63]
The magnitude of the acceleration of the runner is given by:
a= \frac{v_f-v_i}{t}
where
v_f=8.0 m/s is the final speed of the runner
v_i=0 is the initial speed of the runner
t=4.0 s is the time taken

By substituting data into the equation, we find the magnitude of the acceleration:
a= \frac{8.0 m/s -0}{4.0 s}=2 m/s^2
7 0
4 years ago
An automobile accelerates uniformly from a speed of 60 km/hr (16.67 m/s) to a speed of 80 km/hr (22.2 m/s) in 5 s. Determine the
monitta

Answer:

The acceleration is 1.106\ m/s^2 and the distance covered is 97.17 m.

Explanation:

Given that,

Initial speed of an automobile, u = 60 km/hr = 16.67 m/s

Final speed of an automobile, v = 80 km/hr = 22.2 m/s

Time, t = 5 s

We need to find the acceleration of the car and the distance traveled in this 5 sec interval.  Let a is the acceleration. Using the definition of acceleration as :

a=\dfrac{v-u}{t}\\\\a=\dfrac{22.2-16.67}{5}\\\\a=1.106\ m/s^2

Let d is the distance covered. Using the third equation of motion to find it as follows :

v^2-u^2=2as\\\\s=\dfrac{v^2-u^2}{2a}\\\\s=\dfrac{(22.2)^2-(16.67)^2}{2\times 1.106}\\\\s=97.17\ m

So, the acceleration is 1.106\ m/s^2 and the distance covered is 97.17 m.

7 0
3 years ago
If a power lifter raises a 1000N weight a distance of 2 meters in 0.5 seconds, what is his power out put?
Irina18 [472]

Answer:

P = 4000 [W]

Explanation:

In order to solve this problem, we must first determine the work, which is defined as the product of force by distance.

W = F*d

where:

W = work [J] (units in Joules)

F = force = 1000[N]

d = distance = 2 [m]

W = 1000*2

W = 2000 [J]

And power is defined as the relationship between work and the time in which the work is done.

P = W/t

P = power [W] (units of watts)

t = time = 0.5 [s]

P = 2000/0.5

P = 4000 [W]

8 0
3 years ago
g Suppose that you seal an ordinary 60W lightbulb and a suitable battery inside a transparent enclosure and suspend the system f
Lady_Fox [76]

Answer:

kekemeeimdeiddnekem

Explanation:

mdjdjdiddmjd jjeneeiej

5 0
3 years ago
Which of the following statements about dark matter and dark energy is/are true? Choose one or more: Both exceed the matter-ener
cricket20 [7]

Answer:

  • Both exceed the matter-energy equivalent of luminous matter
  • Dark matter has only an attractive gravitational effect, while the dark energy is repulsive in  nature

Explanation:

Dark matter is defined as the matter which consists of about 85% of the total matter of the universe and is no-baryonic in nature.

It is attractive in nature and exerts gravitational pulling effect. Even individual galaxies are under the influence of dark matter. It is way more powerful than the visible matter.

Dark energy is that form of energy which is said to be responsible for the universe's expansion and is repulsive in nature

6 0
3 years ago
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