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KatRina [158]
3 years ago
7

James drew a scaled version of Triangle J using a scale factor of 4 and labeled it Triangle K. The base of triangle J is 5 units

and the height of triangle J is 4. What is the area of triangle K?
Mathematics
2 answers:
Andreas93 [3]3 years ago
8 0

Answer:

The area of triangle K is 16 times greater than the area of triangle J

Step-by-step explanation: so...... If Triangle K is a scaled version of Triangle J

then

Triangle K and Triangle J are similar

erica [24]3 years ago
7 0

Answer:

160

Step-by-step explanation:

If the scale factor is 4, we would have to multiply the height and width by 4

4*5=20

4*4=16

Now to find the area of the triangle using the formula (20*16)/2

That equals to 160

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Yanka [14]

Answer:

(4/3, 7/3)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
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<u>Algebra I</u>

  • Terms/Coefficients
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Step-by-step explanation:

<u>Step 1: Define Systems</u>

7x - y = 7

x + 2y = 6

<u>Step 2: Rewrite Systems</u>

Equation: x + 2y = 6

  1. [Subtraction Property of Equality] Subtract 2y on both sides:                    x = 6 - 2y

<u>Step 3: Redefine Systems</u>

7x - y = 7

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<u>Step 4: Solve for </u><em><u>y</u></em>

<em>Substitution</em>

  1. Substitute in <em>x</em>:                                                                                                7(6 - 2y) - y = 7
  2. Distribute 7:                                                                                                    42 - 14y - y = 7
  3. Combine like terms:                                                                                       42 - 15y = 7
  4. [Subtraction Property of Equality] Subtract 42 on both sides:                    -15y = -35
  5. [Division Property of Equality] Divide -15 on both sides:                             y = 7/3

<u>Step 5: Solve for </u><em><u>x</u></em>

  1. Define original equation:                                                                               x + 2y = 6
  2. Substitute in <em>y</em>:                                                                                                x + 2(7/3) = 6
  3. Multiply:                                                                                                           x + 14/3 = 6
  4. [Subtraction Property of Equality] Subtract 14/3 on both sides:                  x = 4/3
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