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labwork [276]
3 years ago
6

The length of one edge of a cube is 3 units. What is the volume of this cube in cubic units

Mathematics
1 answer:
devlian [24]3 years ago
3 0

Answer:

27 cubic units

Step-by-step explanation:

A cube has equal dimensions. So the volume is 3units × 3units × 3units or 27cubic units

You might be interested in
Which expression is equivalent to the expression -3 (4r - 2) -2r?
liubo4ka [24]

Answer:

-14r + 6

Step-by-step explanation:

-12r + 6 - 2r

3 0
3 years ago
is the equation a true statement when x equals -3 in other words is -3 a solution to the equation 6 x + 5 = 5x +8 + 2x explained
serg [7]

Answer: Yes

Step-by-step explanation: bc 6(-3)+5=5(-3)+8+2(-3)

Becomes -18+5=-15+8+-6 which equals -13 on both sides meaning -3 is a solution

5 0
3 years ago
Read 2 more answers
Use the x-intercept method to find all real solutions of the equation. x^3-9x^2+11x+21=0
IgorLugansk [536]
We must graph y=x^3-9x^2+11x+21. Please, see the attached file.
Then we see were the graph cuts the x-axis, and these values of x are the real solutions of the given equation:

The real solutions of the given equation are:x = -1, 3, and 7

7 0
3 years ago
micheal pays 30 to enter a state fair, plus 4 for each ride. which of the following equations represent his total cost
Shkiper50 [21]

Answer:

I cant see the equation but it should go something along the lines of t = 30 + 4r

Step-by-step explanation:

t = total

r = number of rides

Example: If he went on 4 rides, hen u would imput 4 into r like this

t = 30 + 4 (4)

t = 30 + 16

t = 46

8 0
3 years ago
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
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